JEE Advanced 2023 Paper 2 Online

MCQ (More than One Correct Answer)

-2

The electric field associated with an electromagnetic wave propagating in a dielectric medium is given by $\vec{E}=30(2 \hat{x}+\hat{y}) \sin \left[2 \pi\left(5 \times 10^{14} t-\frac{10^7}{3} z\right)\right] \mathrm{Vm}^{-1}$. Which of the following option(s) is(are) correct?

[Given: The speed of light in vacuum, $c=3 \times 10^8 \mathrm{~m} \mathrm{~s}^{-1}$ ]

$B_x=-2 \times 10^{-7} \sin \left[2 \pi\left(5 \times 10^{14} t-\frac{10^7}{3} z\right)\right] \mathrm{Wb} \mathrm{m}^{-2}$.

$B_y=2 \times 10^{-7} \sin \left[2 \pi\left(5 \times 10^{14} t-\frac{10^7}{3} z\right)\right] \mathrm{Wb} \mathrm{m}^{-2}$.

The wave is polarized in the $x y$-plane with polarization angle $30^{\circ}$ with respect to the $x$-axis.

The refractive index of the medium is 2.

JEE Advanced 2015 Paper 2 Offline

MCQ (More than One Correct Answer)

-2

In terms of potential difference V, electric current I, permittivity $${\varepsilon _0}$$, permeability $${\mu _0}$$ and speed of light c, the dimensionally correct equation(s) is(are) :

$${\mu _0}{I^2} = {\varepsilon _0}{V^2}$$

$${\varepsilon _0}I = {\mu _0}V$$

$$I = {\varepsilon _0}cV$$

$${\mu _0}cI = {\varepsilon _0}V$$

JEE Advanced Subjects