1
JEE Advanced 2023 Paper 2 Online
MCQ (More than One Correct Answer)
+4
-2
The electric field associated with an electromagnetic wave propagating in a dielectric medium is given by $\vec{E}=30(2 \hat{x}+\hat{y}) \sin \left[2 \pi\left(5 \times 10^{14} t-\frac{10^7}{3} z\right)\right] \mathrm{Vm}^{-1}$. Which of the following option(s) is(are) correct?

[Given: The speed of light in vacuum, $c=3 \times 10^8 \mathrm{~m} \mathrm{~s}^{-1}$ ]
A
$B_x=-2 \times 10^{-7} \sin \left[2 \pi\left(5 \times 10^{14} t-\frac{10^7}{3} z\right)\right] \mathrm{Wb} \mathrm{m}^{-2}$.
B
$B_y=2 \times 10^{-7} \sin \left[2 \pi\left(5 \times 10^{14} t-\frac{10^7}{3} z\right)\right] \mathrm{Wb} \mathrm{m}^{-2}$.
C
The wave is polarized in the $x y$-plane with polarization angle $30^{\circ}$ with respect to the $x$-axis.
D
The refractive index of the medium is 2.
2
JEE Advanced 2019 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-1 A conducting wire of parabolic shape, initially y = x2, is moving with velocity $$v = {v_0}\widehat i$$ in a non-uniform magnetic field $$B = {B_0}\left( {1 + {{\left( {{y \over L}} \right)}^\beta }} \right)\widehat k$$, as shown in figure. If V0, B0, L and $$\beta$$ are positive constants and $$\Delta$$$$\phi$$ is the potential difference developed between the ends of the wire, then the correct statement(s) is/are A
$$\left| {\Delta \phi } \right| = {4 \over 3}{B_0}{V_0}L$$ for $$\beta$$ = 2
B
$$\left| {\Delta \phi } \right|$$ remains the same if the parabolic wire is replaced by a straight wire, y =x initially, of length $$\sqrt 2 L$$
C
$$\left| {\Delta \phi } \right|$$ = $${1 \over 2}{B_0}{V_0}L$$ for $$\beta$$ = 0
D
$$\left| {\Delta \phi } \right|$$ is proportional to the length of the wire projected on the y-axis.
3
JEE Advanced 2018 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-1
In the figure below, the switches $${S_1}$$ and $${S_2}$$ are closed simultaneously at $$t=0$$ and a current starts to flow in the circuit. Both the batteries have the same magnitude of the electromotive force (emf) and the polarities are as indicated in the figure. Ignore mutual inductance between the inductors. The current $$I$$ in the middle wire reaches its maximum magnitude $${I_{\max }}$$ at time $$t = \tau$$ . Which of the following statements is (are) true? A
$${I_{\max }} = {V \over {2R}}$$
B
$${I_{max}} = {V \over {4R}}$$
C
$$\tau = {L \over R}\ln 2$$
D
$$\tau = {{2L} \over R}\ln 2$$
4
JEE Advanced 2017 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-1
A circular insulated copper wire loop is twisted to form two loops of area $$A$$ and $$2A$$ as shown in the figure. At the point of crossing the wires remain electrically insulated from each other. The entire loop lies in the plane (of the paper). A uniform magnetic field $$\overrightarrow B$$ points into the plane of the paper. At $$t=0,$$ the loop starts rotating about the common diameter as axis with a constant angular velocity $$\omega$$ in the magnetic field.

Which of the following options is/are correct? A
The emf induced in the loop is proportional to the sum of the areas of the two loops
B
The amplitude of the maximum net emf induced due to both the loops is equal to the amplitude if maximum emf induced in the smaller loop alone
C
The net emf induced due to both the loops is proportional to $$\cos \,\omega t$$
D
The rate of change of the flux is maximum when the plane of the loops is perpendicular to plane of the paper
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