1
MHT CET 2021 23th September Morning Shift
+2
-0

The general solution of the differential equation $$\frac{d y}{d x}=2^{y-x}$$ is

A
$$2^x-2^y=c$$
B
$$\frac{1}{2^x}-\frac{1}{2^y}=c$$
C
$$\frac{1}{2^x}+\frac{1}{2^y}=c$$
D
$$2^x+2^y=c$$
2
MHT CET 2021 23th September Morning Shift
+2
-0

If the surrounding air is kept at $$25^{\circ} \mathrm{C}$$ and a body cools from $$80^{\circ} \mathrm{C}$$ to $$50^{\circ} \mathrm{C}$$ in 30 minutes, then temperature of the body after one hour will be

A
$$31.72^{\circ} \mathrm{C}$$ approximately
B
$$34.74^{\circ} \mathrm{C}$$ approximately
C
$$32.36^{\circ} \mathrm{C}$$ approximately
D
$$36.36^{\circ} \mathrm{C}$$ approximately
3
MHT CET 2021 22th September Evening Shift
+2
-0

The degree of the differential equation whose solution is $$y^2=8 a(x+a)$$, is

A
2
B
1
C
4
D
3
4
MHT CET 2021 22th September Evening Shift
+2
-0

A spherical raindrop evaporates at a rate proportional to its surface area. If its radius originally is 3 mm. and 1 hour later has been reduced to 2 mm, then the expression of radius r of the raindrop at any time t is (where 0 $$\le$$ t < 3)

A
r = t + 5
B
r = t $$-$$ 5
C
r = 3 $$-$$ t
D
r = t + 3
EXAM MAP
Medical
NEET