1
IIT-JEE 2008 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1

Statement 1 : For every chemical reaction at equilibrium, standard Gibbs energy of reaction is zero.

and

Statement 2 : At constant temperature and pressure, chemical reactions are spontaneous in the direction of decreasing Gibbs energy.

A
Statement 1 is True, Statement 2 is True; Statement 2 is correct explanation for Statement 1.
B
Statement 1 is True, Statement 2 is True; Statement 2 is NOT correct explanation for Statement 1.
C
Statement 1 is True, Statement 2 is False.
D
Statement 1 is False, Statement 2 is True.
2
IIT-JEE 2006
MCQ (Single Correct Answer)
+3
-1

$$ \begin{aligned} & \mathrm{Ag}^{+}+\mathrm{NH}_3 \quad\left[\mathrm{Ag}\left(\mathrm{NH}_3\right)\right]^{+} \\ & k_1=3.5 \times 10^{-3} \\ & {\left[\mathrm{Ag}\left(\mathrm{NH}_3\right]^{+}+\mathrm{NH}_3 \quad\left[\mathrm{Ag}\left(\mathrm{NH}_3\right)_2\right]^{+}\right.} \end{aligned} $$

$k_2=1.7 \times 10^{-3}$, then the formation constant of $\left[\mathrm{Ag}\left(\mathrm{NH}_3\right)_2\right]^{+}$ is :

A

$6.08 \times 10^{-6}$

B

$6.08 \times 10^6$

C

$6.08 \times 10^{-9}$

D

None of these

3
IIT-JEE 2006
MCQ (Single Correct Answer)
+3
-1

$$ \mathrm{N}_2+3 \mathrm{H}_2 \to 2 \mathrm{NH}_3 $$

Which is the correct statement if $\mathrm{N}_2$ is added at equilibrium condition?

A

The equilibrium will shift to forward direction because according to second law of thermodynamics, the entropy must increase in the direction of spontaneous reaction.

B

The condition for equilibrium is $\mathrm{G}_{\mathrm{N}_2}+3 \mathrm{G}_{\mathrm{H}_2} \quad 2 \mathrm{G}_{\mathrm{NH}_3}$ where G is Gibbs free energy per mole of the gaseous species measured at that partial pressure. The condition of equilibrium is unaffected by the use of catalyst, which increases the rate of both the forward and backward reactions to the same extent.

C

The catalyst will increase the rate of forward reaction by and that of backward reaction by $\beta$.

D

Catalyst will not alter the rate of either of the reaction.

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