IIT-JEE 2006 | Alternating Current Question 19 | Physics

IIT-JEE 2006

MCQ (Single Correct Answer)

-1

The capacitor of capacitance $C$ can be charged (with the help of a resistance R ) by a voltage source V , by closing switch $\mathrm{S}_1$ while keeping switch $\mathrm{S}_2$ open. The capacitor can be connected in series with an inductor L by closing switch $\mathrm{S}_2$ and opening $\mathrm{S}_1$.

IIT-JEE 2006 Physics - Alternating Current Question 2 English Comprehension

If the total charge stored in the LC circuit.is $\mathrm{Q}_0$, then for $t \geq 0$,

the charge on the capacitor is

$$ \mathrm{Q}=\mathrm{Q}_0 \cos \left(\frac{\pi}{2}+\frac{t}{\sqrt{\mathrm{LC}}}\right) $$

the charge on the capacitor is

$$ \mathrm{Q}=\mathrm{Q}_0 \cos \left(\frac{\pi}{2}-\frac{1}{\sqrt{\mathrm{LC}}}\right) . $$

the charge on the capacitor is

$$ \mathrm{Q}=-\mathrm{LC} \frac{d^2 \mathrm{Q}}{d t^2} . $$

the charge on the capacitor is

$$ \mathrm{Q}=-\frac{1}{\sqrt{\mathrm{LC}}} \frac{d^2 \mathrm{Q}}{d t^2} . $$

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