1
JEE Advanced 2013 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1

A thermal power plant produces electric power of 600 kW at 4000 V, which is to be transported to a place 20 km away from the power plant for consumers' usage. It can be transported either directly with a cable of large current carrying capacity or by using a combination of step-up and step-down transformers at the two ends. The drawback of the direct transmission is the large energy dissipation. In the method using transformers, the dissipation is much smaller. In this method, a step-up transformer is used at the plant side so that the current is reduced to a smaller value. At the consumers' end, a step-down transformer is used to supply power to the consumers at the specified lower voltage. It is reasonable to assume that the power cable is purely resistive and the transformers are ideal with power factor unity. All the currents and voltages mentioned are rms values.

If the direct transmission method with a cable of resistance 0.4 $$\Omega$$ km$$-$$1 is used, the power dissipation (in %) during transmission is

A
20
B
30
C
40
D
50
2
IIT-JEE 2011 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1

A meter bridge is set up as shown, to determine an unknown resistance X using a standard 10 $$\Omega$$ resistor. The galvanometer shows null point when tapping-key is at 52 cm mark. The end-corrections are 1 cm and 2 cm, respectively, for the ends A and B. The determined value of X is

IIT-JEE 2011 Paper 1 Offline Physics - Current Electricity Question 13 English

A
10.2 $$\Omega$$
B
10.6 $$\Omega$$
C
10.8 $$\Omega$$
D
11.1 $$\Omega$$
3
IIT-JEE 2010 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1

Incandescent bulbs are designed by keeping in mind that the resistance of their filament increases with the increase in temperature. If at room temperature, 100, 60 and 40 W bulbs have filament resistances R100, R60 and R40 respectively, the relation between these resistances is

A
$${1 \over {{R_{100}}}} = {1 \over {{R_{40}}}} + {1 \over {{R_{60}}}}$$
B
$${R_{100}} = {R_{40}} + {R_{60}}$$
C
$${R_{100}} > {R_{60}} > {R_{40}}$$
D
$${1 \over {{R_{100}}}} > {1 \over {{R_{60}}}} > {1 \over {{R_{40}}}}$$
4
IIT-JEE 2010 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1

To verify Ohm's law, a student is provided with a test resitor RT, a high resistance R1, a small resistance R2, two identical galvanometers G1 and G2, and a variable voltage source V. The correct circuit to carry out the experiment is

A
IIT-JEE 2010 Paper 1 Offline Physics - Current Electricity Question 8 English Option 1
B
IIT-JEE 2010 Paper 1 Offline Physics - Current Electricity Question 8 English Option 2
C
IIT-JEE 2010 Paper 1 Offline Physics - Current Electricity Question 8 English Option 3
D
IIT-JEE 2010 Paper 1 Offline Physics - Current Electricity Question 8 English Option 4
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