1
MHT CET 2021 23th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $$\mathrm{x}=\mathrm{a}\left(\mathrm{t}-\frac{1}{\mathrm{t}}\right)$$ and $$\mathrm{y}=\mathrm{b}\left(\mathrm{t}+\frac{1}{\mathrm{t}}\right)$$, then $$\frac{\mathrm{dy}}{\mathrm{dx}}=$$

A
$$\frac{a^2 x}{b^2 y}$$
B
$$\frac{a^2 y}{b^2 x}$$
C
$$\frac{-b^2 x}{a^2 y}$$
D
$$\frac{b^2 x}{a^2 y}$$
2
MHT CET 2021 22th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $$y=\tan ^{-1} \sqrt{\frac{1+\cos x}{1-\cos x}}$$, then $$\frac{d y}{d x}=$$

A
1
B
$$\frac{3}{2}$$
C
$$\frac{1}{2}$$
D
$$\frac{-1}{2}$$
3
MHT CET 2021 22th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $$x^y \cdot y^x=16$$, then $\frac{d y}{d x}$ at $(2,2)$$ is

A
$$-$$1
B
0
C
1
D
2
4
MHT CET 2021 22th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $$y^2=a x^2+b x+c$$, where $$a, b, c$$ are constants, then $$y^3 \frac{d^2 y}{d x^2}$$ is equal to

A
function of $$y$$
B
function of both $$\mathrm{x}$$ and $$\mathrm{y}$$
C
constant
D
function of $$x$$
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