1
MHT CET 2025 26th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $\mathrm{f}(x)=\frac{\sin ^2 x}{1+\cot x}+\frac{\cos ^2 x}{1+\tan x}$, then the value of $\mathrm{f}^{\prime}\left(\frac{\pi}{6}\right)$ is equal to

A
0
B
$\frac{1}{2}$
C
$-\frac{1}{2}$
D
$\frac{\sqrt{3}}{2}$
2
MHT CET 2025 25th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $y=\tan ^{-1}\left(\frac{12 x-64 x^3}{1-48 x^2}\right)$, then $\frac{\mathrm{d} y}{\mathrm{~d} x}=$

A
$\frac{3}{1+16 x^2}$
B
$\frac{4}{1+16 x^2}$
C
$\frac{12}{1+16 x^2}$
D
$\frac{1}{1+16 x^2}$
3
MHT CET 2025 25th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

If

$$ \sqrt{y-\sqrt{y-\sqrt{y-\ldots \ldots \ldots \infty}}}=\sqrt{x+\sqrt{x+\sqrt{x+\ldots \ldots \ldots \infty}}} $$

then $\frac{\mathrm{d} y}{\mathrm{~d} x}=$

A
$\frac{y+x+1}{y-x+1}$
B
$\frac{y-x-1}{y-x+1}$
C
$\frac{y-x+1}{y-x-1}$
D
1
4
MHT CET 2025 25th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $\frac{x^2}{\mathrm{a}^2}+\frac{y^2}{\mathrm{~b}^2}=1$, then $\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}$ is

A
$\frac{-b^4}{a}$
B
$\frac{\mathrm{b}^4}{\mathrm{a}^2}$
C
$\frac{-\mathrm{b}^4}{y^3}$
D
$\frac{-b^4}{a^2 \cdot y^3}$
MHT CET Subjects
EXAM MAP