Electrons with de-Broglie wavelength $$\lambda$$ fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-rays is
Some laws/processes are given in Column I. Match these with the physical phenomena given in Column II and indicate your answer by darkening appropriate bubbles in the 4 $$\times$$ 4 matrix given in the ORS.
| Column I | Column II | ||
|---|---|---|---|
| (A) | Transition between two atomic energy levels | (P) | Characteristic X-rays |
| (B) | Electron emission from a material | (Q) | Photoelectric effect |
| (C) | Mosley's law | (R) | Hydrogen spectrum |
| (D) | Change of photon energy into kinetic energy of electrons | (S) | $$\beta$$-decay |
Statement 1 :
If the accelerating potential in an X-ray tube is increased, the wavelengths of the characteristic X-rays do not change.
Statement 2 :
When an electron beam strikes the target in an X-ray tube, part of the kinetic energy is converted into X-ray energy.
The potential energy of a particle of mass m is given by
$$\mathrm{U}(x)=\left\{\begin{array}{cc}\mathrm{E}_{0} & 0 \leq x \leq 1 \\ 0 & x>1\end{array}\right.$$
$$\lambda_{1}$$ and $$\lambda_{2}$$ are the de Broglie wavelengths of the particle, when $$0 \leq x \leq 1$$ and $$x > 1$$, respectively. If the total energy of particle is $$2 \mathrm{E}_{0}$$, find $$\frac{\lambda_{1}}{\lambda_{2}}$$.
JEE Advanced Subjects
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