IIT-JEE 2007 Paper 2 Offline | Dual Nature of Radiation Question 23 | Physics

IIT-JEE 2007 Paper 2 Offline

MCQ (Single Correct Answer)

-1

Electrons with de-Broglie wavelength $$\lambda$$ fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-rays is

$$\lambda_{0}=\frac{2 m c \lambda^{2}}{h}$$

$$\lambda_{0}=\frac{2 h}{m c}$$

$$\lambda_{0}=\frac{2 m^{2} c^{2} \lambda^{3}}{h^{2}}$$

$$\lambda_{0}=\lambda$$

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