1
IIT-JEE 2012 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-2

A small block of mass 0.1 kg lies on a fixed inclined plane PQ which makes an angle $$\theta$$ with the horizontal. A horizontal force of 1 N acts on the block through its centre of mass as shown in the figure. The block remains stationary if (take g = 10 m/s2) A
$$\theta$$ = 45$$^\circ$$
B
$$\theta$$ > 45$$^\circ$$ and a frictional force ats on the block towards P.
C
$$\theta$$ > 45$$^\circ$$ and a frictional force ats on the block towards Q.
D
$$\theta$$ < 45$$^\circ$$ and a frictional force ats on the block towards Q.
2
IIT-JEE 1986
MCQ (More than One Correct Answer)
+2
-0.5
A reference frame attached to the earth
A
is an inertial frame by definition
B
cannot be an inertial frame because the earth is revolving around the sun
C
is an inertial frame because Newton's laws are applicable in this frame
D
cannot be an inertial frame because the earth rotating about its own axis
3
IIT-JEE 1986
MCQ (More than One Correct Answer)
+2
-0.5
A simple pendulum of length L and mass (bob) M is oscillating in a plane about a vertical line between angular limit $$- \phi$$ and $$+ \phi$$. For an angular displacement $$\theta$$ $$\left( {\left| \theta \right| < \phi } \right)$$, the tension in the string and the velocity of the bob are T and V respectively. The following relations hold good under the above conditions:
A
$$T\cos \theta = Mg$$
B
$$T - Mg\cos \theta = {{M{V^2}} \over L}$$
C
The magnitude of the tangential acceleration of the bob $$\left| {{a_T}} \right| = g\sin \theta$$
D
$$T = Mg\cos \theta$$
4
IIT-JEE 1982
MCQ (More than One Correct Answer)
+3
-0.75
In the arrangement shown in Fig. the ends P and Q of an unstretchable string move downwards with uniform speed U. Pulleys A and B are fixed.
Mass M moves upwards with a speed A
$$2U\cos \theta$$
B
$${U \over {\cos \theta }}$$
C
$${{2U} \over {\cos \theta }}$$
D
$$U\cos \theta$$
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