(A) The balanced chemical reaction between CaO and P$$_4$$O$$_{10}$$ is shown below.

$$\mathrm{6CaO+P_4O_{10}\rightarrow 2Ca_3(PO_4)_2}$$

Given, mass of $$\mathrm{P_4O_{10}=852~g}$$

The first step is to calculate the molar mass of $$\mathrm{P_4O_{10}}$$. The molar mass can be used to calculate the number of moles present in the given sample of $$\mathrm{P_4O_{10}}$$.

Molar mass of

$$\mathrm{P_4O_{10}}=4\times31+10\times16=284$$ g

Moles of $$\mathrm{P_4O_{10}}=\frac{\mathrm{Mass~of~P_4O_{10}}}{\mathrm{Molar~mass~of~P_4O_{10}}}=\frac{852}{284}$$

Moles of $$\mathrm{P_4O_{10}}$$ = 3 moles

1 mol of $$\mathrm{P_4O_{10}}$$ reacts with 6 mol of CaO to produce 2 mol of Ca$$_3$$(PO$$_4$$)$$_2$$.

$$\therefore$$ 3 mol of $$\mathrm{P_4O_{10}}$$ will react with 3 $$\times$$ 6 = 18 mol of CaO.

Mass of 1 mol of CaO = 40 + 16 = 56 g

$$\therefore$$ Mass of 18 mol of CaO = 18 $$\times$$ 56 = 1008 g

(B) Structure of $$\mathrm{P_4O_{10}}$$

In $$\mathrm{P_4O_{10}}$$, eqach P atom is bonded to 4 O atoms such that there are three P-O single bonds and one P-O double bond. Two phosphorous atoms share a single O atom.

IIT-JEE 2005 Mains Chemistry - p-Block Elements Question 13 English Explanation 1

Final Answer

(A) 1008 g

(B) IIT-JEE 2005 Mains Chemistry - p-Block Elements Question 13 English Explanation 2

JEE Advanced Subjects