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PREVIOUS
1
JEE Advanced 2014 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-2
In the reaction shown below, the major product(s) formed is/are

JEE Advanced 2014 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 40 English
A
JEE Advanced 2014 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 40 English Option 1
B
JEE Advanced 2014 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 40 English Option 2
C
JEE Advanced 2014 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 40 English Option 3
D
JEE Advanced 2014 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 40 English Option 4
2
JEE Advanced 2013 Paper 2 Offline
MCQ (More than One Correct Answer)
+4
-2

After completion of the reactions (I and II), the organic compound(s) in the reaction mixtures is(are)

JEE Advanced 2013 Paper 2 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 28 English

A
Reaction I : P and Reaction II : P
B
Reaction I : U, acetone and Reaction II : Q, acetone
C
Reaction I : T, U, acetone and Reaction II : P
D
Reaction I : R, acetone and Reaction II : S, acetone
3
IIT-JEE 2012 Paper 2 Offline
MCQ (More than One Correct Answer)
+4
-2

With reference to the scheme given, which of the given statement(s) about T, U, V and W is(are) correct?

IIT-JEE 2012 Paper 2 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 20 English

A
T is soluble in hot aqueous NaOH.
B
U is optically active.
C
Molecular formula of W is C10H18O4.
D
V gives effervescence on treatment with aqueous NaHCO3.
4
IIT-JEE 2012 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-2

Identify the binary mixtures that can be separated into individual compounds, by differential extraction, as shown in the given scheme.

IIT-JEE 2012 Paper 1 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 15 English

A
C6H5OH and C6H5COOH
B
C6H5COOH and C6H5CH2OH
C
C6H5CH2OH and C6H5OH
D
C6H5CH2OH and C6H5CH2COOH
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