1
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If $y^{\frac{1}{m}} + y^{\frac{-1}{m}} = 2x$ , then $(x^2 - 1)y_1^{\ 2} =$
A
$my^2$
B
$m^2 y^2$
C
$m^2 y$
D
$my$
2
MHT CET 2026 15th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $y = \tan^{-1}\sqrt{\dfrac{1 + \sin 2x}{1 - \sin 2x}}$, then $\dfrac{\text{d}y}{\text{d}x}$ at $x = \dfrac{\pi}{6}$ is
A
$0$
B
$1$
C
$\dfrac{1}{2}$
D
$\dfrac{\sqrt{3}}{2}$
3
MHT CET 2026 15th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The derivative of $\sin\left(\log\left(\dfrac{x+3}{x}\right)\right)$ is
A
$\dfrac{3}{x+3}\cos\left(\log\left(\dfrac{x+3}{x}\right)\right)$
B
$\dfrac{3}{x(x+3)}\cos\left(\log\left(\dfrac{x+3}{x}\right)\right)$
C
$\dfrac{-3}{x(x+3)}\cos\left(\log\left(\dfrac{x+3}{x}\right)\right)$
D
$\dfrac{-1}{x(x+3)}\cos\left(\log\left(\dfrac{x+3}{x}\right)\right)$
4
MHT CET 2026 15th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $e^y + xy = e$, then the ordered pair $\left(\dfrac{\text{d}y}{\text{d}x}, \dfrac{\text{d}^2 y}{\text{d}x^2}\right)$ at $x = 0$ is equal to
A
$\left(\dfrac{1}{e}, \dfrac{-1}{e^2}\right)$
B
$\left(\dfrac{-1}{e}, \dfrac{1}{e^2}\right)$
C
$\left(\dfrac{1}{e}, \dfrac{1}{e^2}\right)$
D
$\left(\dfrac{-1}{e}, \dfrac{-1}{e^2}\right)$

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