1
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If $f(x) = \cos x \cos 2x \cos 4x \cos 8x \cos 16x$, then $f'\left(\dfrac{\pi}{4}\right)$ is equal to
A
$1$
B
$0$
C
$\sqrt{2}$
D
$\dfrac{1}{\sqrt{2}}$
2
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
Let f(x) be a twice differentiable function such that $f''(x) = -f(x)$, $f'(x) = g(x)$ and $h(x) = \{f(x)\}^2 + \{g(x)\}^2$. If $h(5) = 11$, then $h(10)$ is equal to ...
A
$11$
B
$22$
C
$0$
D
Not defined
3
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $\cot[f(x)] = \dfrac{3x - x^3}{1 - 3x^2}$ and $\sin[g(x)] = \dfrac{1 - x^2}{1 + x^2}$, then $\lim\limits_{x \to t}\dfrac{f(x) - f(t)}{g(x) - g(t)} = \ldots$
A
$\dfrac{3}{2(1 + t^2)}$
B
$\dfrac{3}{2}$
C
$\dfrac{5}{2}$
D
$-\dfrac{5}{2(1 + t^2)}$
4
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $y = \cos^{-1}\left(\dfrac{1 - 4^x}{1 + 4^x}\right)$, then $\dfrac{dy}{dx}$ at $x = 1$ is
A
$\dfrac{4\log 2}{5}$
B
$\dfrac{\log 2}{5}$
C
$\dfrac{2\log 8}{5}$
D
$\dfrac{5\log 8}{2}$

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