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### JEE Advanced 2014 Paper 1 Offline

Numerical
During Searle's experiment, zero of the Vernier scale lies between 3.20 $\times$ 10-2 m and 3.25 $\times$ 10-2 m of the main scale. The 20th division of the Vernier scale exactly coincides with one of the main scale divisions. When an additional load of 2 kg is applied to the wire, the zero of the Vernier scale still lies between 3.20 $\times$ 10-2 m and 3.25 $\times$ 10-2 m of the main scale but now the 45th division of Vernier scale coincides with one of the main scale divisions. The length of the thin metallic wire is 2 m and its cross-sectional area is 8 $\times$ 10-7 m2. The least count of the Vernier scale is 1.0 $\times$ 10-5 m. The maximum percentage error in the Young's modulus of the wire is

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JEE Advanced 2019 Paper 2 Offline (1)
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JEE Advanced 2015 Paper 2 Offline (1)
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JEE Advanced 2014 Paper 1 Offline (2)
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