IIT-JEE 2010 Paper 2 Offline | Chemical Bonding & Molecular Structure Question 24 | Chemistry

IIT-JEE 2010 Paper 2 Offline

MCQ (Single Correct Answer)

-0.5

Assuming that Hund’s rule is violated, the bond order and magnetic nature of the diatomic molecule B₂ is

1 and diamagnetic

0 and diamagnetic

1 and paramagnetic

0 and paramagnetic

IIT-JEE 2010 Paper 2 Offline

MCQ (Single Correct Answer)

-0.5

The species having pyramidal shape is

SO₃

BrF₃

$$SiO_3^{2-}$$

OSF₂

IIT-JEE 2009 Paper 1 Offline

MCQ (Single Correct Answer)

-0

Match each of the diatomic molecules in Column I with its property/properties in Column II:

$$\mathrm{(A)\to(P),(Q),(R),(T);(B)\to(S),(T);(C)\to(P),(Q);(D)\to(P),(Q),(S)}$$

$$\mathrm{(A)\to(P),(S),(R),(T);(B)\to(S),(T);(C)\to(P),(Q);(D)\to(P),(T),(S)}$$

$$\mathrm{(A)\to(Q),(R),(T);(B)\to(P),(T);(C)\to(P),(Q);(D)\to(T),(Q),(S)}$$

$$\mathrm{(A)\to(P),(R),(T);(B)\to(Q),(T);(C)\to(S),(Q);(D)\to(P),(Q),(S)}$$

IIT-JEE 2007 Paper 1 Offline

MCQ (Single Correct Answer)

-1

The species having bond order different from that in CO is :

NO$$^-$$

NO$$^+$$

CN$$^-$$

N$$_2$$

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