IIT-JEE 2010 Paper 2 Offline | Chemical Bonding & Molecular Structure Question 19 | Chemistry

IIT-JEE 2010 Paper 2 Offline

MCQ (Single Correct Answer)

-0.5

Assuming that Hund’s rule is violated, the bond order and magnetic nature of the diatomic molecule B₂ is

1 and diamagnetic

0 and diamagnetic

1 and paramagnetic

0 and paramagnetic

IIT-JEE 2009 Paper 1 Offline

MCQ (Single Correct Answer)

-0

Match each of the diatomic molecules in Column I with its property/properties in Column II:

$$\mathrm{(A)\to(P),(Q),(R),(T);(B)\to(S),(T);(C)\to(P),(Q);(D)\to(P),(Q),(S)}$$

$$\mathrm{(A)\to(P),(S),(R),(T);(B)\to(S),(T);(C)\to(P),(Q);(D)\to(P),(T),(S)}$$

$$\mathrm{(A)\to(Q),(R),(T);(B)\to(P),(T);(C)\to(P),(Q);(D)\to(T),(Q),(S)}$$

$$\mathrm{(A)\to(P),(R),(T);(B)\to(Q),(T);(C)\to(S),(Q);(D)\to(P),(Q),(S)}$$

IIT-JEE 2007

MCQ (Single Correct Answer)

-0.5

Among the following the paramagnetic compound is

Na₂O₂

O₃

N₂O

KO₂

IIT-JEE 2007

MCQ (Single Correct Answer)

-0.5

The species having bond order different from that in CO is

NO^-

NO⁺

CN^-

N₂

JEE Advanced Subjects