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JEE Advanced 2015 Paper 1 Offline
Numerical
+4
-0
A Young's double slit interference arrangement with slits S1 and S2 is immersed in water (refractive index = 4/3) as shown in the figure. The positions of maxima on the surface of water are given by x2 = p2m2$$\lambda$$2 $$-$$ d2, where $$\lambda$$ is the wavelength of light in air (refractive index = 1). 2d is the separation between the slits and m is an integer. The value of p is
JEE Advanced 2015 Paper 1 Offline Physics - Wave Optics Question 9 English
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