1
JEE Advanced 2017 Paper 2 Offline
MCQ (More than One Correct Answer)
+4
-1
A uniform magnetic field $$B$$ exist in the region between $$x=0$$ and $$x = {{3R} \over 2}$$ (region $$2$$ in the figure) pointing normally into the plane of the paper. A particle with charge $$+Q$$ and momentum $$p$$ directed along $$x$$-axis enters region $$2$$ from region $$1$$\$ at point $${P_1}\left( y \right) = - R).$$ Which of the following option(s) is/are correct?

A
For $$B > {2 \over 3}{p \over {QR}}$$ the particle well re-enter region $$1$$
B
For $$B = {8 \over {13}}{p \over {QR}},$$ the particle will enter region $$3$$ through the point $${P_2}$$ on $$x$$-axis
C
When the particle re-enters region $$1$$ through the longest possible path in region $$2,$$ the magnitude of the change in its linear momentum between point $${P_1}$$ and the farthest point from $$y$$-axis is $$p/\sqrt 2$$
D
For a fixed $$B,$$ particles of same charge $$Q$$ and same velocity $$v,$$ the distance between the point $${P_1}$$ and the point of re-entry into region $$1$$ is inversely proportional to the mass of the particle
2
JEE Advanced 2015 Paper 2 Offline
MCQ (More than One Correct Answer)
+4
-2

In a thin rectangular metallic strip a constant current I flows along the positive x-direction, as shown in the figure. The length, width and thickness of the strip are l, w and d, respectively.

A uniform magnetic field B is applied on the strip along the positive y-direction. Due to this, the charge carriers experience a net deflection along the z-direction. This results in accumulation of charge carriers on the surface PQRS and appearance of equal and opposite charges on the face opposite PQRS. A potential difference along the z-direction is thus developed. Charge accumulation continues until the magnetic force is balanced by the electric force. The current is assumed to be uniformly distributed on the cross section of the strip and carried by electrons.

Consider two different metallic strips (1 and 2) of the same material. Their lengths are the same, widths are w1 and w2 and thickness are d1 and d2, respectively. Two points K and M are symmetrically located on the opposite faces parallel to the x-y plane (see figure). V1 and V2 are the potential differences between K and M in strips 1 and 2, respectively. Then, for a given current I flowing through them in a given magnetic field strength B, the correct statements is/are
A
If w1 = w2 and d1 = 2d2, then V2 = 2V1
B
If w1 = w2 and d1 = 2d2, then V2 = V1
C
If w1 = 2w2 and d1 = d2, then V2 = 2V1
D
If w1 = 2w2 and d1 = d2, then V2 = V1
3
JEE Advanced 2015 Paper 2 Offline
MCQ (More than One Correct Answer)
+4
-2

In a thin rectangular metallic strip a constant current I flows along the positive x-direction, as shown in the figure. The length, width and thickness of the strip are l, w and d, respectively.

A uniform magnetic field B is applied on the strip along the positive y-direction. Due to this, the charge carriers experience a net deflection along the z-direction. This results in accumulation of charge carriers on the surface PQRS and appearance of equal and opposite charges on the face opposite PQRS. A potential difference along the z-direction is thus developed. Charge accumulation continues until the magnetic force is balanced by the electric force. The current is assumed to be uniformly distributed on the cross section of the strip and carried by electrons.

Consider two different metallic strips (1 and 2) of same dimensions (length l, width w and thickness d) with carrier densities n1 and n2, respectively. Strip 1 is placed in magnetic field B1 and strip 2 is placed in magnetic field B2, both along positive y-directions. Then V1 and V2 are the potential differences developed between K and M in strips 1 and 2, respectively. Assuming that the current I is the same for both the strips, the correct options is/are :
A
If B1 = B2 and n1 = 2n2, then V2 = 2V1
B
If B1 = B2 and n1 = 2n2, then V2 = V1
C
If B1 = 2B2 and n1 = n2, then V2 = 0.5V1
D
If B1 = 2B2 and n1 = n2, then V2 = V1
4
JEE Advanced 2015 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-2
A conductor (shown in the figure) carrying constant current I is kept in the x-y plane in a uniform magnetic field B. If F is the magnitude of the total magnetic force acting on the conductor, then the correct statements is/are
A
if B is along $$\widehat z$$, F $$\propto$$ (L + R)
B
if B is along $$\widehat x$$, F = 0
C
if B is along $$\widehat y$$, F $$\propto$$ (L + R)
D
if B is along $$\widehat z$$, F = 0
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