1
IIT-JEE 1986
MCQ (More than One Correct Answer)
+2
-0.5
A simple pendulum of length L and mass (bob) M is oscillating in a plane about a vertical line between angular limit $$ - \phi $$ and $$ + \phi $$. For an angular displacement $$\theta $$ $$\left( {\left| \theta \right| < \phi } \right)$$, the tension in the string and the velocity of the bob are T and V respectively. The following relations hold good under the above conditions:
A
$$T\cos \theta = Mg$$
B
$$T - Mg\cos \theta = {{M{V^2}} \over L}$$
C
The magnitude of the tangential acceleration of the bob $$\left| {{a_T}} \right| = g\sin \theta $$
D
$$T = Mg\cos \theta $$
2
IIT-JEE 1982
MCQ (More than One Correct Answer)
+3
-0.75
In the arrangement shown in Fig. the ends P and Q of an unstretchable string move downwards with uniform speed U. Pulleys A and B are fixed.
Mass M moves upwards with a speed IIT-JEE 1982 Physics - Laws of Motion Question 22 English
A
$$2U\cos \theta $$
B
$${U \over {\cos \theta }}$$
C
$${{2U} \over {\cos \theta }}$$
D
$$U\cos \theta $$
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