1
JEE Advanced 2021 Paper 2 Online
Numerical
+2
-0
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A sample (5.6 g) containing iron is completely dissolved in cold dilute HCl to prepare a 250 mL of solution. Titration of 25.0 mL of this solution requires 12.5 mL of 0.03 M KMnO4 solution to reach the end point. Number of moles of Fe2+ present in 250 mL solution is x $$\times$$ 10$$-$$2 (consider complete dissolution of FeCl2). The amount of iron present in the sample is y% by weight.

(Assume : KMnO4 reacts only with Fe2+ in the solution

Use : Molar mass of iron as 56 g mol$$-$$1)

The value of x is ______.
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2
JEE Advanced 2021 Paper 2 Online
Numerical
+2
-0
Change Language
A sample (5.6 g) containing iron is completely dissolved in cold dilute HCl to prepare a 250 mL of solution. Titration of 25.0 mL of this solution requires 12.5 mL of 0.03 M KMnO4 solution to reach the end point. Number of moles of Fe2+ present in 250 mL solution is x $$\times$$ 10$$-$$2 (consider complete dissolution of FeCl2). The amount of iron present in the sample is y% by weight.

(Assume : KMnO4 reacts only with Fe2+ in the solution

Use : Molar mass of iron as 56 g mol$$-$$1)

The value of y is ______.
Your input ____
3
JEE Advanced 2021 Paper 2 Online
Numerical
+4
-0
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Ozonolysis of ClO2 produces an oxide of chlorine. The average oxidation state of chlorine in this oxide is __________.
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4
JEE Advanced 2016 Paper 1 Offline
Numerical
+3
-0
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In neutral or faintly alkaline solution, 8 moles of permanganate anion quantitative oxidise thiosulphate anions to produce X moles of a sulphur containing product. The magnitude of X is....
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