IIT-JEE 2007 Paper 2 Offline | Laws of Motion Question 21 | Physics

IIT-JEE 2007 Paper 2 Offline

MCQ (Single Correct Answer)

-1

A particle moves in the X - Y plane under the influence of a force such that its linear momentum is $$\overrightarrow p \left( t \right) = A\left[ {\widehat i\cos (kt) - \widehat j\sin (kt)} \right]$$, where A and k are constants. The angle between the force and the momentum is

$$0^\circ $$

$$30^\circ $$

$$45^\circ $$

$$90^\circ $$

IIT-JEE 2007 Paper 2 Offline

MCQ (Single Correct Answer)

-1

STATEMENT 1

A cloth covers a table. Some dishes are kept on it. The cloth can be pulled out without dislodging the dishes from the table.

Because

STATEMENT 2

For every action there is an equal and opposite reaction.

Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.

Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1s.

Statement-1 is True, Statement-2 is False.

Statement-1 is False, Statement-2 is True.

IIT-JEE 2001 Screening

MCQ (Single Correct Answer)

-0.5

The pulleys and strings shown in the figure are smooth and of negligible mass. For the system to remain in equilibrium, the angle $$\theta $$ should be IIT-JEE 2001 Screening Physics - Laws of Motion Question 20 English

IIT-JEE 2001 Screening Physics - Laws of Motion Question 20 English

$$0^\circ $$

$$30^\circ $$

$$45^\circ $$

$$60^\circ $$

IIT-JEE 1994

MCQ (Single Correct Answer)

-0.25

A block of mass 0.1 is held against a wall applying a horizontal force of 5 N on the block. If the coefficient of friction between the block and the wall is 0.5, the magnitude of the frictional force acting on the block is:

2.5 N

0.98 N

4.9 N

0.49 N

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