JEE Advanced 2016 Paper 1 Offline | Units & Measurements Question 18 | Physics

JEE Advanced 2016 Paper 1 Offline

MCQ (More than One Correct Answer)

-1

A length-scale (l) depends on the permittivity ($$\varepsilon $$) of a dielectric material, Boltzmann constant (k_B), the absolute temperature (T), the number per unit volume (n) of certain charged particles, and the charge (q) carried by each of the particles. Which of the following expression(s) for I is(are) dimensionally correct?

$$l = \sqrt {\left( {{{n{q^2}} \over {\varepsilon {k_b}T}}} \right)} $$

$$l = \sqrt {\left( {{{\varepsilon {k_b}T} \over {n{q^2}}}} \right)} $$

$$l = \sqrt {\left( {{{{q^2}} \over {\varepsilon {n^{2/3}}{k_B}T}}} \right)} $$

$$l = \sqrt {\left( {{{{q^2}} \over {\varepsilon {n^{1/3}}{k_B}T}}} \right)} $$

JEE Advanced 2015 Paper 2 Offline

MCQ (More than One Correct Answer)

-2

In terms of potential difference V, electric current I, permittivity $${\varepsilon _0}$$, permeability $${\mu _0}$$ and speed of light c, the dimensionally correct equation(s) is(are) :

$${\mu _0}{I^2} = {\varepsilon _0}{V^2}$$

$${\varepsilon _0}I = {\mu _0}V$$

$$I = {\varepsilon _0}cV$$

$${\mu _0}cI = {\varepsilon _0}V$$

JEE Advanced 2015 Paper 1 Offline

MCQ (More than One Correct Answer)

-2

Planck's constant h, speed of light c and gravitational constant G are used to form a unit of length L and a unit of mass M. Then the correct option(s) is(are)

$$M \propto \sqrt c $$

$$M \propto \sqrt G $$

$$L \propto \sqrt h $$

$$L \propto \sqrt G $$

JEE Advanced 2015 Paper 1 Offline

MCQ (More than One Correct Answer)

-2

Consider a Vernier callipers in which each 1 cm on the main scale is divided into 8 equal divisions and a screw gauge with 100 divisions on its circular scale. In the Vernier callipers, 5 divisions of the Vernier scale coincide with 4 divisions on the main scale and in the screw gauge, one complete rotation of the circular scale moves it by two divisions on the linear scale. Then:

If the pitch of the screw gauge is twice the least count of the Vernier callipers, the least count of the screw gauge is 0.01 mm.

If the pitch of the screw gauge is twice the least count of the Vernier callipers, the least count of the screw gauge is 0.005 mm.

If the least count of the linear scale of the screw gauge is twice the least count of the Vernier callipers, the least count of the screw gauge is 0.01 mm.

If the least count of the linear scale of the screw gauge is twice the least count of the Vernier callipers, the least count of the screw gauge is 0.005 mm.

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