1

JEE Advanced 2023 Paper 2 Online

Numerical

+4

-0

$50 \mathrm{~mL}$ of 0.2 molal urea solution (density $=1.012 \mathrm{~g} \mathrm{~mL}^{-1}$ at $300 \mathrm{~K}$ ) is mixed with $250 \mathrm{~mL}$ of a solution containing $0.06 \mathrm{~g}$ of urea. Both the solutions were prepared in the same solvent. The osmotic pressure (in Torr) of the resulting solution at $300 \mathrm{~K}$ is _______.

[Use: Molar mass of urea $=60 \mathrm{~g} \mathrm{~mol}^{-1}$; gas constant, $\mathrm{R}=62$ L Torr $\mathrm{K}^{-1} \mathrm{~mol}^{-1}$;

Assume, $\Delta_{\text {mix }} \mathrm{H}=0, \Delta_{\text {mix }} \mathrm{V}=0$ ]

[Use: Molar mass of urea $=60 \mathrm{~g} \mathrm{~mol}^{-1}$; gas constant, $\mathrm{R}=62$ L Torr $\mathrm{K}^{-1} \mathrm{~mol}^{-1}$;

Assume, $\Delta_{\text {mix }} \mathrm{H}=0, \Delta_{\text {mix }} \mathrm{V}=0$ ]

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2

JEE Advanced 2022 Paper 2 Online

Numerical

+3

-1

An aqueous solution is prepared by dissolving $0.1 \mathrm{~mol}$ of an ionic salt in $1.8 \mathrm{~kg}$ of water at $35^{\circ} \mathrm{C}$. The salt remains $90 \%$ dissociated in the solution. The vapour pressure of the solution is $59.724 \mathrm{~mm}$ of Hg. Vapor pressure of water at $35{ }^{\circ} \mathrm{C}$ is $60.000 \mathrm{~mm}$ of $\mathrm{Hg}$. The number of ions present per formula unit of the ionic salt is _________.

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3

JEE Advanced 2021 Paper 1 Online

Numerical

+2

-0

The boiling point of water in a 0.1 molal silver nitrate solution (solution A) is x$$^\circ$$C. To this solution A, an equal volume of 0.1 molal aqueous barium chloride solution is added to make a new solution B. The difference in the boiling points of water in the two solutions A and B is y $$\times$$ 10

(Assume : Densities of the solutions A and B are the same as that of water and the soluble salts dissociate completely.

Use : Molal elevation constant (Ebullioscopic Constant), K

^{$$-$$2}$$^\circ$$C.(Assume : Densities of the solutions A and B are the same as that of water and the soluble salts dissociate completely.

Use : Molal elevation constant (Ebullioscopic Constant), K

_{b}= 0.5 K kg mol^{$$-$$1}; Boiling point of pure water as 100$$^\circ$$C.)The value of x is ________.

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4

JEE Advanced 2021 Paper 1 Online

Numerical

+2

-0

The boiling point of water in a 0.1 molal silver nitrate solution (solution A) is x$$^\circ$$C. To this solution A, an equal volume of 0.1 molal aqueous barium chloride solution is added to make a new solution B. The difference in the boiling points of water in the two solutions A and B is y $$\times$$ 10

(Assume : Densities of the solutions A and B are the same as that of water and the soluble salts dissociate completely.

Use : Molal elevation constant (Ebullioscopic Constant), K

^{$$-$$2}$$^\circ$$C.(Assume : Densities of the solutions A and B are the same as that of water and the soluble salts dissociate completely.

Use : Molal elevation constant (Ebullioscopic Constant), K

_{b}= 0.5 K kg mol^{$$-$$1}; Boiling point of pure water as 100$$^\circ$$C.)The value of | y | is ________.

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Questions Asked from Solutions (Numerical)

Number in Brackets after Paper Indicates No. of Questions

JEE Advanced 2023 Paper 2 Online (1)
JEE Advanced 2022 Paper 2 Online (1)
JEE Advanced 2021 Paper 1 Online (2)
JEE Advanced 2020 Paper 2 Offline (1)
JEE Advanced 2019 Paper 1 Offline (1)
JEE Advanced 2018 Paper 1 Offline (2)
JEE Advanced 2016 Paper 1 Offline (1)
JEE Advanced 2014 Paper 1 Offline (2)
IIT-JEE 2006 (1)

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