1
GATE ECE 2015 Set 1
MCQ (Single Correct Answer)
+1
-0.3
The result of the convolution $$x\left( { - t} \right) * \delta \left( { - t - {t_0}} \right)$$ is
A
$$x\left( {t + {t_0}} \right)\,$$
B
$$x\left( {t - {t_0}} \right)\,$$
C
$$x\left( { - t + {t_0}} \right)$$
D
$$\,x\left( { - t - {t_0}} \right)$$
2
GATE ECE 2013
MCQ (Single Correct Answer)
+1
-0.3
Two system with impulse responses h1(t) and h2(t) are connected in cascade. Then the overall impulse response of the cascaded system is given by
A
Product of h1(t) and h2(t).
B
Sum of h1(t) and h2(t).
C
Convolution of h1(t) and h2(t).
D
Subtraction of h1(t) and h2(t)
3
GATE ECE 2013
MCQ (Single Correct Answer)
+1
-0.3
The impulse response of a system is h(t) = t u(t). For an input u(t - 1), the output is
A
$${{{t^2}} \over 2}u\left( t \right)$$
B
$${{t\left( {t - 1} \right)} \over 2}u\left( {t - 1} \right)$$
C
$${{{{\left( {t - 1} \right)}^2}} \over 2}u\left( {t - 1} \right)\,$$
D
$${{{t^2} - 1} \over 2}u\left( {t - 1} \right)$$
4
GATE ECE 2011
MCQ (Single Correct Answer)
+1
-0.3
The differential equation $$100{{{d^2}y} \over {dt}} - 20{{dy} \over {dt}} + y = x\left( t \right)$$ describes a system with an input x(t) and output y(t). The system, which is initially relaxed, is excited by a unit step input. The output y(t) can be represented by the waveform
A
GATE ECE 2011 Signals and Systems - Continuous Time Linear Invariant System Question 40 English Option 1
B
GATE ECE 2011 Signals and Systems - Continuous Time Linear Invariant System Question 40 English Option 2
C
GATE ECE 2011 Signals and Systems - Continuous Time Linear Invariant System Question 40 English Option 3
D
GATE ECE 2011 Signals and Systems - Continuous Time Linear Invariant System Question 40 English Option 4
GATE ECE Subjects
EXAM MAP
Medical
NEETAIIMS
Graduate Aptitude Test in Engineering
GATE CSEGATE ECEGATE EEGATE MEGATE CEGATE PIGATE IN
Civil Services
UPSC Civil Service
Defence
NDA
Staff Selection Commission
SSC CGL Tier I
CBSE
Class 12