1
GATE ECE 2012
MCQ (Single Correct Answer)
+1
-0.3
The impedance looking into nodes 1 and 2 in the given circuit is
2
GATE ECE 2012
MCQ (Single Correct Answer)
+1
-0.3
In the circuit shown below, current through the inductor is
3
GATE ECE 2012
MCQ (Single Correct Answer)
+1
-0.33
The average power delivered to an impedance $(4-j 3) \Omega$ by a current $5 \cos (100 \pi t+100) A$ is
4
GATE ECE 2009
MCQ (Single Correct Answer)
+1
-0.3
In the interconnection of ideal sources shown in the figure, it is known that the 60V source is absorbing power.
Which of the following can be the value of the current source I?
Questions Asked from Network Elements (Marks 1)
Number in Brackets after Paper Indicates No. of Questions
GATE ECE 2022 (2)
GATE ECE 2021 (1)
GATE ECE 2017 Set 2 (1)
GATE ECE 2015 Set 1 (1)
GATE ECE 2014 Set 4 (1)
GATE ECE 2014 Set 3 (1)
GATE ECE 2014 Set 1 (1)
GATE ECE 2013 (1)
GATE ECE 2012 (3)
GATE ECE 2009 (1)
GATE ECE 2004 (1)
GATE ECE 2002 (2)
GATE ECE 2001 (1)
GATE ECE 2000 (2)
GATE ECE 1998 (2)
GATE ECE 1997 (4)
GATE ECE 1995 (1)
GATE ECE 1993 (1)
GATE ECE Subjects
Signals and Systems
Representation of Continuous Time Signal Fourier Series Discrete Time Signal Fourier Series Fourier Transform Discrete Time Signal Z Transform Continuous Time Linear Invariant System Transmission of Signal Through Continuous Time LTI Systems Discrete Time Linear Time Invariant Systems Sampling Continuous Time Signal Laplace Transform Discrete Fourier Transform and Fast Fourier Transform Transmission of Signal Through Discrete Time Lti Systems Miscellaneous Fourier Transform
Network Theory
Control Systems
Digital Circuits
General Aptitude
Electronic Devices and VLSI
Analog Circuits
Engineering Mathematics
Microprocessors
Communications
Electromagnetics