GATE ECE 2002 | Oscillators Question 4 | Analog Circuits

GATE ECE 2002

MCQ (Single Correct Answer)

-0.6

The circuit in the figure employs positive Feedback and is intended to generate sinusoidal oscillation. If at a frequency f$$_0$$, B(f)= $${{\Delta {V_f}(f)} \over {{V_0}(f)}} = {1 \over 6}\,\,\angle {0^0}$$ then to sustain oscillation at this frequency.

$${R_2}\, = \,5\,\,{R_1}$$

$${R_2}\, = \,6\,\,{R_1}$$

$${R_2}\, = {{{R_1}} \over 5}$$

$${R_2}\, = {{{R_1}} \over 6}$$

GATE ECE 2001

MCQ (Single Correct Answer)

-0.6

The Oscillator circuit shown in the figure is GATE ECE 2001 Analog Circuits - Oscillators Question 5 English

Hartley Oscillator with $${f_{oscillation}}$$= 79.6 MHz

Colpitts Oscillator with $${f_{oscillation}}$$ =50.3 MHz

Hartley Oscillator with $${f_{oscillation}}$$= 159.2 MHz

Colpitts Oscillator with $${f_{oscillation}}$$=159.2 MHz

GATE ECE 1996

MCQ (Single Correct Answer)

-0.6

Value of R in the oscillator shown in the given figure. So chosen that it just oscillates at an angular frequencies of' "$$\omega $$". The value of "$$\omega $$" and the required value of R will respectively be GATE ECE 1996 Analog Circuits - Oscillators Question 6 English

GATE ECE 1996 Analog Circuits - Oscillators Question 6 English

$${10^5}$$ rad/ sec, 2 $$ \times $$$${10^4}$$ $$\Omega $$

$$2 \times {10^4}$$ rad/ sec, $$2 \times {10^4}$$ $$\Omega $$

$$2 \times {10^4}$$ rad/ sec , $${10^5}\,\Omega $$

$${10^{5\,\,}}rad/\sec ,{10^5}\,\Omega $$

GATE ECE 1994

Subjective

-0

Match the following.

GROUP-1
(A) Hartley
(B) Wein-bridge
(C) Crystal

GROUP-2
(1) Low frequency oscillator
(2) High frequency oscillator
(3) Stable frequency oscillator
(4) Relaxation oscillator
(5) Nagative Resistance oscillator