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1
GATE ECE 2012
MCQ (Single Correct Answer)
+1
-0.3

In the circuit shown below, current through the inductor is

GATE ECE 2012 Network Theory - Network Elements Question 35 English
A
$$\frac2{1\;+\;\mathrm j}\mathrm A$$
B
$$\frac{-1}{1\;+\;\mathrm j}\mathrm A$$
C
$$\frac1{1\;+\;\mathrm j}\mathrm A$$
D
0 A
2
GATE ECE 2012
MCQ (Single Correct Answer)
+1
-0.3

The impedance looking into nodes 1 and 2 in the given circuit is

GATE ECE 2012 Network Theory - Network Elements Question 34 English
A
50 Ω
B
100 Ω
C
5 kΩ
D
10.1 kΩ
3
GATE ECE 2012
MCQ (Single Correct Answer)
+1
-0.33
The average power delivered to an impedance $(4-j 3) \Omega$ by a current $5 \cos (100 \pi t+100) A$ is
A
$44.2 \mathrm{~W}$
B
$50 \mathrm{~W}$
C
$62.5 \mathrm{~W}$
D
$125 \mathrm{~W}$
4
GATE ECE 2009
MCQ (Single Correct Answer)
+1
-0.3

In the interconnection of ideal sources shown in the figure, it is known that the 60V source is absorbing power.

GATE ECE 2009 Network Theory - Network Elements Question 36 English

Which of the following can be the value of the current source I?

A
10 A
B
13 A
C
15 A
D
18 A
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