1
JEE Advanced 2023 Paper 2 Online
MCQ (More than One Correct Answer)
+4
-2
Change Language
Let $f:(0,1) \rightarrow \mathbb{R}$ be the function defined as $f(x)=[4 x]\left(x-\frac{1}{4}\right)^2\left(x-\frac{1}{2}\right)$, where $[x]$ denotes the greatest integer less than or equal to $x$. Then which of the following statements is(are) true?
A
The function $f$ is discontinuous exactly at one point in $(0,1)$
B
There is exactly one point in $(0,1)$ at which the function $f$ is continuous but NOT differentiable
C
The function $f$ is NOT differentiable at more than three points in $(0,1)$
D
The minimum value of the function $f$ is $-\frac{1}{512}$
2
JEE Advanced 2023 Paper 2 Online
MCQ (More than One Correct Answer)
+4
-2
Change Language
Let $S$ be the set of all twice differentiable functions $f$ from $\mathbb{R}$ to $\mathbb{R}$ such that $\frac{d^2 f}{d x^2}(x)>0$ for all $x \in(-1,1)$. For $f \in S$, let $X_f$ be the number of points $x \in(-1,1)$ for which $f(x)=x$. Then which of the following statements is(are) true?
A
There exists a function $f \in S$ such that $X_f=0$
B
For every function $f \in S$, we have $X_f \leq 2$
C
There exists a function $f \in S$ such that $X_f=2$
D
There does NOT exist any function $f$ in $S$ such that $X_f=1$
3
JEE Advanced 2023 Paper 2 Online
Numerical
+4
-0
Change Language
For $x \in \mathbb{R}$, let $\tan ^{-1}(x) \in\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$. Then the minimum value of the function $f: \mathbb{R} \rightarrow \mathbb{R}$ defined by $f(x)=\int\limits_0^{x \tan ^{-1} x} \frac{e^{(t-\cos t)}}{1+t^{2023}} d t$ is :
Your input ____
4
JEE Advanced 2023 Paper 2 Online
Numerical
+4
-0
Change Language
For $x \in \mathbb{R}$, let $y(x)$ be a solution of the differential equation

$\left(x^2-5\right) \frac{d y}{d x}-2 x y=-2 x\left(x^2-5\right)^2$ such that $y(2)=7$.

Then the maximum value of the function $y(x)$ is :
Your input ____
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