IIT-JEE 2009 Paper 1 Offline | JEE Advanced Year Wise Previous Years Questions - ExamSIDE.Com

Joint Entrance Examination

Medical

Graduate Aptitude Test in Engineering

CBSE

1

IIT-JEE 2009 Paper 1 Offline

MCQ (Single Correct Answer)

+3

-1

Match each of the compounds in Column I with its characteristic reaction(s) in Column II.

	Column I		Column II
(A)	$$C{H_3}C{H_2}C{H_2}CN$$	(P)	Reduction with $$Pd - C/{H_2}$$
(B)	$$C{H_3}C{H_2}OCOC{H_3}$$	(Q)	Reduction with $$SnC{l_2}/HCl$$
(C)	$$C{H_3} - CH = CH - C{H_2}OH$$	(R)	Development of foul smell on treatment with chloroform and alcoholic KOH
(D)	$$C{H_3}C{H_2}C{H_2}C{H_2}N{H_2}$$	(S)	Reduction with diisobutylaluminium hydride (DIBAL-H)
		(T)	Alkaline hydrolysis

A

$$\mathrm{(A)\to(P),(Q),(S),(T);(B)\to(Q),(T);(C)\to(P);(D)\to(S)}$$

B

$$\mathrm{(A)\to(Q), (R), (S),(T);(B)\to(S),(T);(C)\to(P);(D)\to(R)}$$

C

$$\mathrm{(A)\to(P),(R),(S),(T);(B)\to(S),(T);(C)\to(P);(D)\to(R), (T)}$$

D

$$\mathrm{(A)\to(P),(Q),(S),(T);(B)\to(S),(T);(C)\to(P);(D)\to(R)}$$

2

IIT-JEE 2009 Paper 1 Offline

MCQ (Single Correct Answer)

+3

-1

Let $$z = \,\cos \,\theta \, + i\,\sin \,\theta $$ . Then the value of $$\sum\limits_{m = 1}^{15} {{\mathop{\rm Im}\nolimits} } ({z^{2m - 1}})\,at\,\theta \, = {2^ \circ }$$ is

A

$${1 \over {\sin \,{2^ \circ }}}$$

B

$${1 \over {3\sin \,{2^ \circ }}}$$

C

$${1 \over {2\sin \,{2^ \circ }}}$$

D

$${1 \over {4\sin \,{2^ \circ }}}$$

3

IIT-JEE 2009 Paper 1 Offline

MCQ (Single Correct Answer)

+3

-1

Let $$z = x + iy$$ be a complex number where x and y are integers. Then the area of the rectangle whose vertices are the roots of the equation $$\overline z {z^3} + z{\overline z ^3} = 350$$ is

A

48

B

32

C

40

D

80

4

IIT-JEE 2009 Paper 1 Offline

MCQ (More than One Correct Answer)

+4

-2

If $${{{{\sin }^4}x} \over 2} + {{{{\cos }^4}x} \over 3} = {1 \over 5},$$ then

A

$${\tan ^2}x = {2 \over 3}$$

B

$${{{{\sin }^8}x} \over 8} + {{{{\cos }^8}x} \over {27}} = {1 \over {125}}$$

C

$${\tan ^2}x = {1 \over 3}$$

D

$${{{{\sin }^8}x} \over 8} + {{{{\cos }^8}x} \over {27}} = {2 \over {125}}$$

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