1
IIT-JEE 2000
Subjective
+4
-0
The fourth power of the common difference of an arithmatic progression with integer entries is added to the product of any four consecutive terms of it. Prove that the resulting sum is the square of an integer.
2
IIT-JEE 2000
Subjective
+5
-0
A coin probability $$p$$ of showing head when tossed. It is tossed $$n$$ times. Let $${p_n}$$ denote the probability that no two (or more) consecutive heads occur. Prove that $${p_1} = 1,\,\,{p_2} = 1 - {p^2}$$ and $${p_n} = \left( {1 - p} \right).\,\,{p_{n - 1}} + p\left( {1 - p} \right){p_{n - 2}}$$ for all $$n \ge 3.$$
Prove by induction on, that $${p_n} = A{\alpha ^n} + B{\beta ^n}$$ for all $$n \ge 1,$$ where $$\alpha $$ and $$\beta $$ are the roots of quadratic equation $${x^2} - \left( {1 - p} \right)x - p\left( {1 - p} \right) = 0$$ and $$A = {{{p^2} + \beta - 1} \over {\alpha \beta - {\alpha ^2}}},B = {{{p^2} + \alpha - 1} \over {\alpha \beta - {\beta ^2}}}.$$
3
IIT-JEE 2000
Subjective
+6
-0
Let $$a,\,b,\,c$$ be possitive real numbers such that $${b^2} - 4ac > 0$$ and let $${\alpha _1} = c.$$ Prove by induction that $${\alpha _{n + 1}} = {{a\alpha _n^2} \over {\left( {{b^2} - 2a\left( {{\alpha _1} + {\alpha _2} + ... + {\alpha _n}} \right)} \right)}}$$ is well-defined and
$${\alpha _{n + 1}} < {{{\alpha _n}} \over 2}$$ for all $$n = 1,2,....$$ (Here, 'well-defined' means that the denominator in the expression for $${\alpha _{n + 1}}$$ is not zero.)
$${\alpha _{n + 1}} < {{{\alpha _n}} \over 2}$$ for all $$n = 1,2,....$$ (Here, 'well-defined' means that the denominator in the expression for $${\alpha _{n + 1}}$$ is not zero.)
4
IIT-JEE 2000
Subjective
+6
-0
For every possitive integer $$n$$, prove that
$$\sqrt {\left( {4n + 1} \right)} < \sqrt n + \sqrt {n + 1} < \sqrt {4n + 2}.$$
Hence or otherwise, prove that $$\left[ {\sqrt n + \sqrt {\left( {n + 1} \right)} } \right] = \left[ {\sqrt {4n + 1} \,\,} \right],$$
where $$\left[ x \right]$$ denotes the gratest integer not exceeding $$x$$.
$$\sqrt {\left( {4n + 1} \right)} < \sqrt n + \sqrt {n + 1} < \sqrt {4n + 2}.$$
Hence or otherwise, prove that $$\left[ {\sqrt n + \sqrt {\left( {n + 1} \right)} } \right] = \left[ {\sqrt {4n + 1} \,\,} \right],$$
where $$\left[ x \right]$$ denotes the gratest integer not exceeding $$x$$.
Paper Analysis
Total Questions
Chemistry 6
Mathematics 16
Physics 1
More Papers of JEE Advanced
JEE Advanced 2026 Paper 2 Online JEE Advanced 2026 Paper 1 Online JEE Advanced 2025 Paper 2 Online JEE Advanced 2025 Paper 1 Online JEE Advanced 2024 Paper 2 Online JEE Advanced 2024 Paper 1 Online JEE Advanced 2023 Paper 2 Online JEE Advanced 2023 Paper 1 Online JEE Advanced 2022 Paper 2 Online JEE Advanced 2022 Paper 1 Online JEE Advanced 2021 Paper 2 Online JEE Advanced 2021 Paper 1 Online JEE Advanced 2020 Paper 2 Offline JEE Advanced 2020 Paper 1 Offline JEE Advanced 2019 Paper 2 Offline JEE Advanced 2019 Paper 1 Offline JEE Advanced 2018 Paper 2 Offline JEE Advanced 2018 Paper 1 Offline JEE Advanced 2017 Paper 2 Offline JEE Advanced 2017 Paper 1 Offline JEE Advanced 2016 Paper 2 Offline JEE Advanced 2016 Paper 1 Offline JEE Advanced 2015 Paper 2 Offline JEE Advanced 2015 Paper 1 Offline JEE Advanced 2014 Paper 2 Offline JEE Advanced 2014 Paper 1 Offline JEE Advanced 2013 Paper 2 Offline JEE Advanced 2013 Paper 1 Offline IIT-JEE 2012 Paper 2 Offline IIT-JEE 2012 Paper 1 Offline IIT-JEE 2011 Paper 2 Offline IIT-JEE 2011 Paper 1 Offline IIT-JEE 2010 Paper 1 Offline IIT-JEE 2010 Paper 2 Offline IIT-JEE 2009 Paper 2 Offline IIT-JEE 2009 Paper 1 Offline IIT-JEE 2008 Paper 2 Offline IIT-JEE 2008 Paper 1 Offline IIT-JEE 2007 Paper 2 Offline IIT-JEE 2007 Paper 1 Offline IIT-JEE 2006 IIT-JEE 2005 Screening IIT-JEE 2005 IIT-JEE 2005 Mains IIT-JEE 2004 IIT-JEE 2004 Screening IIT-JEE 2003 IIT-JEE 2003 Screening IIT-JEE 2002 Screening IIT-JEE 2002 IIT-JEE 2001 IIT-JEE 2001 Screening IIT-JEE 2000 IIT-JEE 2000 Screening IIT-JEE 1999 Screening IIT-JEE 1999 IIT-JEE 1998 Screening IIT-JEE 1998 IIT-JEE 1997 IIT-JEE 1996 IIT-JEE 1995 IIT-JEE 1995 Screening IIT-JEE 1994 IIT-JEE 1993 IIT-JEE 1992 IIT-JEE 1991 IIT-JEE 1990 IIT-JEE 1989 IIT-JEE 1988 IIT-JEE 1987 IIT-JEE 1986 IIT-JEE 1985 IIT-JEE 1984 IIT-JEE 1983 IIT-JEE 1982 IIT-JEE 1981 IIT-JEE 1980 IIT-JEE 1979 IIT-JEE 1978
JEE Advanced Papers
All year-wise previous year question papers
2006
1997
1996
1994
1993
1992
1991
1990
1989
1988
1987
1986
1985
1984
1983
1982
1981
1980
1979
1978