Read the following statement and explanation and answer as per the options given below

ASSERTION : The first ionization energy of Be is greater than that of B.

REASON : 2p orbital is lower in energy than 2s.

Molecular shape of SF₄, CF₄ and XeF₄ are

The hybridisation of atomic orbitals of nitrogen in $$NO_2^+$$, $$NO_3^-$$ and $$NH_4^+$$ are

For all $$x \in \left( {0,1} \right)$$