1
IIT-JEE 2000 Screening
MCQ (Single Correct Answer)
+2
-0.5
For all $$x \in \left( {0,1} \right)$$
2
IIT-JEE 2000 Screening
MCQ (Single Correct Answer)
+2
-0.5
Let $$f\left( x \right) = \left\{ {\matrix{
{\left| x \right|,} & {for} & {0 < \left| x \right| \le 2} \cr
{1,} & {for} & {x = 0} \cr
} } \right.$$ then at $$x=0$$, $$f$$ has
3
IIT-JEE 2000 Screening
MCQ (Single Correct Answer)
+3
-0.75
If $$f\left( x \right) = \left\{ {\matrix{
{{e^{\cos x}}\sin x,} & {for\,\,\left| x \right| \le 2} \cr
{2,} & {otherwise,} \cr
} } \right.$$ then $$\int\limits_{ - 2}^3 {f\left( x \right)dx = } $$
4
IIT-JEE 2000 Screening
MCQ (Single Correct Answer)
+2
-0.5
Let $$g\left( x \right) = \int\limits_0^x {f\left( t \right)dt,} $$ where f is such that
$${1 \over 2} \le f\left( t \right) \le 1,$$ for $$t \in \left[ {0,1} \right]$$ and $$\,0 \le f\left( t \right) \le {1 \over 2},$$ for $$t \in \left[ {1,2} \right]$$.
Then $$g(2)$$ satisfies the inequality
$${1 \over 2} \le f\left( t \right) \le 1,$$ for $$t \in \left[ {0,1} \right]$$ and $$\,0 \le f\left( t \right) \le {1 \over 2},$$ for $$t \in \left[ {1,2} \right]$$.
Then $$g(2)$$ satisfies the inequality
Paper analysis
Total Questions
Chemistry
9
Mathematics
31
Physics
3
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