1
GATE ECE 2007
MCQ (Single Correct Answer)
+2
-0.6
The open-loop transfer function of a plant is given as $$G(s) = {1 \over {{s^2} - 1}}.$$ If the plant is operated in a unity feedback configuration, then the lead compensator that can stabilize this control system is
A
$${{10\left( {s - 1} \right)} \over {s + 2}}$$
B
$${{10\left( {s + 4} \right)} \over {s + 2}}$$
C
$${{10\left( {s + 2} \right)} \over {s + 10}}$$
D
$${{2\left( {s + 2} \right)} \over {s + 10}}$$
2
GATE ECE 2007
MCQ (Single Correct Answer)
+2
-0.6
A control system with a PD controller is shown in the figure. If the velocity error constant $${K_v} = 1000$$ and the damping ratio $$\zeta = 0.5,$$ then the values of $${K_P}$$ and $${K_D}$$ are GATE ECE 2007 Control Systems - Compensators Question 13 English
A
$${K_P} = 100,{K_D} = 0.09$$
B
$${K_P} = 100,{K_D} = 0.9$$
C
$${K_P} = 10,{K_D} = 0.09$$
D
$${K_P} = 10,{K_D} = 0.9$$
3
GATE ECE 2007
MCQ (Single Correct Answer)
+2
-0.6
The asymptotic Bode plot of a transfer function is shown in the figure. the transfer function G(s) corresponding to this bode plot is GATE ECE 2007 Control Systems - Frequency Response Analysis Question 26 English
A
$${1 \over {\left( {s + 1} \right)\left( {s + 20} \right)}}$$
B
$${1 \over {s\left( {s + 1} \right)\left( {s + 20} \right)}}$$
C
$${{100} \over {s\left( {s + 1} \right)\left( {s + 20} \right)}}$$
D
$${{100} \over {s\left( {s + 1} \right)\left( {1 + 0.05s} \right)}}$$
4
GATE ECE 2007
MCQ (Single Correct Answer)
+2
-0.6
The transfer function of a plant is $$$T\left(s\right)=\frac5{\left(s+5\right)\left(s^2+s+1\right)}$$$ The second-order approximation of T (s) using dominant pole concept is:
A
$$\frac1{\left(s+5\right)\left(s+1\right)}$$
B
$$\frac5{\left(s+5\right)\left(s+1\right)}$$
C
$$\frac5{\left(s^2+s+1\right)}$$
D
$$\frac1{\left(s^2+s+1\right)}$$