1
GATE ECE 2007
MCQ (Single Correct Answer)
+2
-0.6
For the circuit shown, the counter state (Q1 Q0) follows the sequence GATE ECE 2007 Digital Circuits - Sequential Circuits Question 38 English
A
00,01,10,11,00......
B
00,01,10,00,01.......
C
00,01,11,00,01.....
D
00,10,11,00,10......
2
GATE ECE 2007
MCQ (Single Correct Answer)
+2
-0.6
In the following circuit, X is given by GATE ECE 2007 Digital Circuits - Combinational Circuits Question 31 English
A
$$X = \,A\overline B \,\overline C + \overline A \,B\,\overline C + \overline A \,\overline B C + ABC$$
B
$$X = \,\overline A \,BC + A\overline B C + AB\overline C + \overline A \,\overline B \,\overline C $$
C
$$X = AB + BC + AC$$
D
$$X = \,\overline A \,\overline B \, + \overline B \,\overline C \, + \overline A \,\overline C $$
3
GATE ECE 2007
MCQ (Single Correct Answer)
+2
-0.6
The Boolean expression Y= $$\overline A \,\overline B \,\overline C \,D + \overline A BC\overline D + A\overline {B\,} \overline C \,D + AB\overline C \,\overline D $$
A
Y = $$\overline A \,\overline B \,\overline C \,D + \overline A B\overline C + A\overline C D$$
B
Y = $$\overline A \,\overline B \,\overline C \,D + BC\overline D + A\overline B \overline C \,D$$
C
Y=$$ \overline A \,BC\,\overline D + \overline B \,\overline C D + A\overline B \overline C \,D$$
D
Y= $$\overline A \,BC\,\overline D + \overline B \,\overline C D + AB\overline C \,\overline D $$
4
GATE ECE 2007
MCQ (Single Correct Answer)
+1
-0.3
The Boolean function Y=AB+CD is to be realized using only 2-input NAND gates. The minimum number of gates required is
A
2
B
3
C
4
D
5
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