1
GATE ECE 2007
MCQ (Single Correct Answer)
+2
-0.6
The transfer function of a plant is $$$T\left(s\right)=\frac5{\left(s+5\right)\left(s^2+s+1\right)}$$$ The second-order approximation of T (s) using dominant pole concept is:
A
$$\frac1{\left(s+5\right)\left(s+1\right)}$$
B
$$\frac5{\left(s+5\right)\left(s+1\right)}$$
C
$$\frac5{\left(s^2+s+1\right)}$$
D
$$\frac1{\left(s^2+s+1\right)}$$
2
GATE ECE 2007
MCQ (Single Correct Answer)
+1
-0.3
If the closed-loop transfer function of a control system is given as T(s)=$${{s - 5} \over {(s + 2)(s + 3)}},$$ then it is
A
an unstable system
B
an uncontrollable system
C
a minimum phase system
D
a non-minimum phase system
3
GATE ECE 2007
MCQ (Single Correct Answer)
+2
-0.6
The asymptotic Bode plot of a transfer function is shown in the figure. the transfer function G(s) corresponding to this bode plot is GATE ECE 2007 Control Systems - Frequency Response Analysis Question 21 English
A
$${1 \over {\left( {s + 1} \right)\left( {s + 20} \right)}}$$
B
$${1 \over {s\left( {s + 1} \right)\left( {s + 20} \right)}}$$
C
$${{100} \over {s\left( {s + 1} \right)\left( {s + 20} \right)}}$$
D
$${{100} \over {s\left( {s + 1} \right)\left( {1 + 0.05s} \right)}}$$
4
GATE ECE 2007
MCQ (Single Correct Answer)
+2
-0.6
The open-loop transfer function of a plant is given as $$G(s) = {1 \over {{s^2} - 1}}.$$ If the plant is operated in a unity feedback configuration, then the lead compensator that can stabilize this control system is
A
$${{10\left( {s - 1} \right)} \over {s + 2}}$$
B
$${{10\left( {s + 4} \right)} \over {s + 2}}$$
C
$${{10\left( {s + 2} \right)} \over {s + 10}}$$
D
$${{2\left( {s + 2} \right)} \over {s + 10}}$$
EXAM MAP
Medical
NEET
Graduate Aptitude Test in Engineering
GATE CSEGATE ECEGATE EEGATE MEGATE CEGATE PIGATE IN
CBSE
Class 12