GATE ECE 2004 | GATE ECE Year Wise Previous Years Questions

GATE ECE 2004

MCQ (Single Correct Answer)

-0.6

For the circuit shown in Figure, the initial conditions are zeros. Its transfer function $$H(s) = {{{V_c}\,(s)} \over {{V_i}\,(s)}}$$ is GATE ECE 2004 Network Theory - Two Port Networks Question 20 English

GATE ECE 2004 Network Theory - Two Port Networks Question 20 English

$${1 \over {{s^2}\, + \,{{10}^6}\,s\, + \,{{10}^6}}}$$

$${{{{10}^6}} \over {{s^2}\, + \,{{10}^3}\,s\, + \,{{10}^6}}}$$

$${{{{10}^3}} \over {{s^2}\, + \,{{10}^3}\,s\, + \,{{10}^6}}}$$

$${{{{10}^6}} \over {{s^2}\, + \,{{10}^6}\,s\, + \,{{10}^6}}}$$

GATE ECE 2004

MCQ (Single Correct Answer)

-0.3

The Fourier transform of a conjugate symmetric function is always

imaginary

conjugate anti-symmetric

real

conjugate symmetric

GATE ECE 2004

MCQ (Single Correct Answer)

-0.3

The z transform of a system is
H(z) = $${z \over {z - 0.2}}$$ .
If the ROC is $$\left| {z\,} \right|$$ < 0.2, then the impulse response of the system is

$${(0.2)^n}\,u\left[ n \right]$$

$${(0.2)^n}\,u\left[ { - n - 1} \right]$$

$$ - {(0.2)^n}\,u\left[ n \right]$$

$$ - {(0.2)^n}\,u\left[ { - n - 1} \right]$$

GATE ECE 2004

MCQ (Single Correct Answer)

-0.6

A system described by the differential equation: $${{{d^2}y} \over {d{t^2}}} + 3{{dy} \over {dt}} + 2y = x(t)$$ is initially at rest. For input x(t) = 2u(t), the output y(t) is

$$(1 - 2{e^{ - t}} + {e^{ - 2t}})\,u(t)$$

$$(1 + 2{e^{ - t}} - 2\,{e^{ - 2t}})\,u(t)$$

$$(0.5 + {e^{ - t}} + 1.5\,{e^{ - 2t}})\,u(t)$$

$$(0.5 + 2{e^{ - t}} + 2\,\,{e^{ - 2t}})\,u(t)$$

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