GATE ECE 2004 | GATE ECE Year Wise Previous Years Questions

GATE ECE 2004

MCQ (Single Correct Answer)

-0.6

The circuit shown in Fig, has initial current $${\mathrm i}_\mathrm L\left(0^-\right)\;=\;1\;\mathrm A$$ through the inductor and an initial voltage $${\mathrm v}_\mathrm C\left(0^-\right)\;=\;-1\;\mathrm V$$ across the capacitor. For input v(t) = u(t), the Laplace transform of the current i(t) for t ≥ 0 is

GATE ECE 2004 Network Theory - Transient Response Question 31 English

$$\frac s{s^2\;+\;s\;+\;1}$$

$$\frac{s\;+\;2}{s^2\;+\;s\;+\;1}$$

$$\frac{s\;-\;1}{s^2\;+\;s\;+\;1}$$

$$\frac{s\;+\;1}{s^2\;+\;s\;+\;1}$$

GATE ECE 2004

MCQ (Single Correct Answer)

-0.3

For the R-L circuit shown in Fig, the input voltage. v_i(t) = u (t) The current i(t) is GATE ECE 2004 Network Theory - Transient Response Question 48 English

GATE ECE 2004 Network Theory - Transient Response Question 48 English Option 1

GATE ECE 2004 Network Theory - Transient Response Question 48 English Option 2

GATE ECE 2004

MCQ (Single Correct Answer)

-0.3

The equivalent inductance measured between the terminals 1 and 2 for the circuit shown in figure, is

GATE ECE 2004 Network Theory - Network Elements Question 36 English

L₁ + L₂ + M

L₁ + L₂ - M

L₁ + L₂ + 2M

L₁ + L₂ - 2M

GATE ECE 2004

MCQ (Single Correct Answer)

-0.6

Let x(t) and y(t) (with Fourier transforms X(f) and Y(f) respectively) be related as shown in Fig.(1) & (2). GATE ECE 2004 Signals and Systems - Fourier Transform Question 14 English

GATE ECE 2004 Signals and Systems - Fourier Transform Question 14 English

Then Y(f) is

$$ - {1 \over 2}X(f/2){e^{ - j2\pi f}}$$

$$ - {1 \over 2}X(f/2){e^{j2\pi f}}$$

$$ - X(f/2){e^{j2\pi f}}$$

$$ - X(f/2){e^{ - j2\pi f}}$$

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