GATE ECE 2004 | GATE ECE Year Wise Previous Years Questions

GATE ECE 2004

MCQ (Single Correct Answer)

-0.3

An AM signal is detected using an envelope detector. The carrier frequency and modulating signal frequency are 1 MHz and 2 KHz respectively. An appropriate value for the time constant of the envelope detector is

500 µsec

20 µsec

0.2 µsec

1 µsec

GATE ECE 2004

MCQ (Single Correct Answer)

-0.6

A system described by the following differential equation $$$\frac{d^2y}{dt^2}+3\frac{dy}{dt}+2y=x\left(t\right)$$$ is initially at rest. For input x(t) = 2u(t), the output y(t) is

$$\left(1-2e^{-t}+e^{-2t}\right)u\left(t\right)$$

$$\left(1+2e^{-t}-2e^{-2t}\right)u\left(t\right)$$

$$\left(0.5+e^{-t}+1.5e^{-2t}\right)u\left(t\right)$$

$$\left(0.5+2e^{-t}+2e^{-2t}\right)u\left(t\right)$$

GATE ECE 2004

MCQ (Single Correct Answer)

-0.6

Consider the signal flow graph shown in Figure. The gain $$\frac{x_5}{x_1}$$ is GATE ECE 2004 Control Systems - Signal Flow Graph and Block Diagram Question 4 English

GATE ECE 2004 Control Systems - Signal Flow Graph and Block Diagram Question 4 English

$$\frac{1-\left(be\;+\;cf\;+\;dg\right)}{abcd}$$

$$\frac{bedg}{1-\left(be\;+\;cf\;+\;dg\right)}$$

$$\frac{abcd}{1-\left(be\;+\;cf\;+\;dg\right)\;+\;bedg}$$

$$\frac{1-\left(be\;+\;cf\;+\;dg\right)\;+\;bedg}{abcd}$$

GATE ECE 2004

MCQ (Single Correct Answer)

-0.6

Consider the Bode magnitude plot shown in figure. The transfer function H(s) is GATE ECE 2004 Control Systems - Frequency Response Analysis Question 37 English

GATE ECE 2004 Control Systems - Frequency Response Analysis Question 37 English

$${{\left( {s + 10} \right)} \over {\left( {s + 1} \right)\left( {s + 100} \right)}}$$

$${{10\left( {s + 1} \right)} \over {\left( {s + 10} \right)\left( {s + 100} \right)}}$$

$${{{{10}^2}\left( {s + 1} \right)} \over {\left( {s + 10} \right)\left( {s + 100} \right)}}$$

$${{{{10}^3}\left( {s + 100} \right)} \over {\left( {s + 1} \right)\left( {s + 10} \right)}}$$

PREVIOUS NEXT

GATE ECE Papers

2024