1
GATE ECE 2004
MCQ (Single Correct Answer)
+1
-0.3
For the R-L circuit shown in Fig, the input voltage. vi(t) = u (t) The current i(t) is GATE ECE 2004 Network Theory - Transient Response Question 45 English
A
GATE ECE 2004 Network Theory - Transient Response Question 45 English Option 1
B
GATE ECE 2004 Network Theory - Transient Response Question 45 English Option 2
C
GATE ECE 2004 Network Theory - Transient Response Question 45 English Option 3
D
GATE ECE 2004 Network Theory - Transient Response Question 45 English Option 4
2
GATE ECE 2004
MCQ (Single Correct Answer)
+2
-0.6

The circuit shown in Fig, has initial current $${\mathrm i}_\mathrm L\left(0^-\right)\;=\;1\;\mathrm A$$ through the inductor and an initial voltage $${\mathrm v}_\mathrm C\left(0^-\right)\;=\;-1\;\mathrm V$$ across the capacitor. For input v(t) = u(t), the Laplace transform of the current i(t) for t ≥ 0 is

GATE ECE 2004 Network Theory - Transient Response Question 28 English
A
$$\frac s{s^2\;+\;s\;+\;1}$$
B
$$\frac{s\;+\;2}{s^2\;+\;s\;+\;1}$$
C
$$\frac{s\;-\;1}{s^2\;+\;s\;+\;1}$$
D
$$\frac{s\;+\;1}{s^2\;+\;s\;+\;1}$$
3
GATE ECE 2004
MCQ (Single Correct Answer)
+2
-0.6

Consider the following statements S1 and S2.

S1: The $$\beta$$ of a bipolar transistor reduces if the base width is increased.

S2: The $$\beta$$ of a bipolar transistor increases if the doping concentration in the base in increased

Which one of the following is correct?
A
S1 is FALSE and S2 is TRUE
B
Both S1 and S2 are TRUE
C
S1 is TRUE and S2 is FALSE
D
Both S1 and S2 are FALSE
4
GATE ECE 2004
MCQ (Single Correct Answer)
+1
-0.3
For the circuit shown in figure, the time constant $$RC = 1$$ $$ms$$. The input voltage is $${v_i}\left( t \right) = \sqrt 2 \,\sin \,{10^3}t$$. The output voltage $${v_0}\left( t \right)$$ is equal to GATE ECE 2004 Network Theory - Sinusoidal Steady State Response Question 38 English
A
$$\sin \left( {{{10}^3}t - {{45}^0}} \right)$$
B
$$\sin \left( {{{10}^3}t + {{45}^0}} \right)$$
C
$$\sin \left( {{{10}^3}t - {{53}^0}} \right)$$
D
$$\sin \left( {{{10}^3}t + {{53}^0}} \right)$$
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