1
GATE ECE 2004
MCQ (Single Correct Answer)
+2
-0.6
Consider the sequence

$$x[n] = [ - \,4 - \,j5,\,\mathop {1 + j2}\limits_ \uparrow ,\,\,4]$$

The conjugate anti-symmetric part of the sequence is

A
$$\left[ {\matrix{ { - 4 - j\,\,2.5} & {j\,2} & {4 - j\,\,2.5} \cr } } \right]$$
B
$$\left[ {\matrix{ { - j\,\,2.5} & 1 & { - j\,\,2.5} \cr } } \right]$$
C
$$\left[ {\matrix{ { - j\,\,5} & {j\,2} & 0 \cr } } \right]$$
D
$$\left[ {\matrix{ { - 4} & 1 & 4 \cr } } \right]$$
2
GATE ECE 2004
MCQ (Single Correct Answer)
+2
-0.6
A causal system having the transfer function H(s) = $${1 \over {s + 2}}$$, is excited with 10 u(t). The time at which the output reaches 99% of its steady state value is
A
2.7 sec
B
2.5 sec
C
2.3 sec
D
2.1 sec
3
GATE ECE 2004
MCQ (Single Correct Answer)
+2
-0.6
A rectangular pulse train s(t) as shown in Fig.1 is convolved with the signal $${\cos ^2}$$ ($$4\pi \,{10^{3\,}}$$t). The convolved signal will be a GATE ECE 2004 Signals and Systems - Continuous Time Linear Invariant System Question 26 English
A
DC
B
12 kHz sinusoid
C
8 kHz sinusoid
D
14 kHz sinusoid
4
GATE ECE 2004
MCQ (Single Correct Answer)
+2
-0.6
A system described by the differential equation: $${{{d^2}y} \over {d{t^2}}} + 3{{dy} \over {dt}} + 2y = x(t)$$ is initially at rest. For input x(t) = 2u(t), the output y(t) is
A
$$(1 - 2{e^{ - t}} + {e^{ - 2t}})\,u(t)$$
B
$$(1 + 2{e^{ - t}} - 2\,{e^{ - 2t}})\,u(t)$$
C
$$(0.5 + {e^{ - t}} + 1.5\,{e^{ - 2t}})\,u(t)$$
D
$$(0.5 + 2{e^{ - t}} + 2\,\,{e^{ - 2t}})\,u(t)$$
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