$$ \text { Reaction between } \mathrm{CH}_3 \mathrm{COCH}_3 \text { and } \mathrm{NH}_2 \mathrm{OH} \text { : } $$

IIT-JEE 2006 Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 7 English Explanation 1 The oxime formed is optically inactive as there is plane of symmetry present in it.

Reaction between $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COCH}_3$ and $\mathrm{NH}_2 \mathrm{OH}$

IIT-JEE 2006 Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 7 English Explanation 2 An oxime will be obtained which shows two enantiomers based on the position of bulky group, $\mathrm{CH}_3 \mathrm{CH}_2$ with respect to the OH group attached to N atom of the oxime.

The two enantiomers of the above compound are:

IIT-JEE 2006 Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 7 English Explanation 3 The two enantiomers are optically active as they lack a plane of symmetry and exist as $R$ and S isomers.

Hence, 3 different oximes are formed out of which 2 are optically active and one is optically inactive.

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