1
JEE Advanced 2013 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1

The reaction of Cl2 gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two (different) oxoacids of chlorine, P and Q, respectively. The Cl2 gas reacts with SO2 gas, in presence of charcoal, to give a product R. R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus, T.

R, S and T respectively, are

A
SO2Cl2, PCl5 and H3PO4
B
SO2Cl2, PCl3 and H3PO3
C
SOCl2, PCl3 and H3PO2
D
SOCl2, PCl5 and H3PO4
2
JEE Advanced 2013 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1

The unbalanced chemical reactions given in List I show missing reagent or condition (?) which are provided in List II. Match List I with List II and select the correct answer using the code given below the lists :

List I List II
P. $$Pb{O_2} + {H_2}S{O_4}\buildrel ? \over
\longrightarrow PbS{O_4} + {O_2} + Other\,products$$
1. NO
Q. $$N{a_2}{S_2}{O_3} + {H_2}O\buildrel ? \over
\longrightarrow NaHS{O_4} + Other\,products$$
2. $${I_2}$$
R. $${N_2}{H_4}\buildrel ? \over
\longrightarrow {N_2} + Other\,products$$
3. Warm
S. $$Xe{F_2}\buildrel ? \over
\longrightarrow Xe + Other\,products$$
4. $$C{l_2}$$

A
P-4, Q-2, R-3, S-1
B
P-3, Q-2, R-1, S-4
C
P-1, Q-4, R-2, S-3
D
P-3, Q-4, R-2, S-1
3
JEE Advanced 2013 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1

Concentrated nitric acid, upon long standing, turns yellow-brown due to the formation of

A
NO
B
NO2
C
N2O
D
N2O4
4
IIT-JEE 2012 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1

The reaction of white phosphorous with aqueous NaOH gives phosphine along with another phosphorus containing compound. The reaction type; the oxidation states of phosphorus in phosphine and the other product are, respectively,

A
redox reaction; $$-$$3 and $$-$$5
B
redox reaction; +3 and +5
C
disproportionation reaction; $$-$$3 and +1
D
disproportionation reaction; $$-$$3 and +3
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