1
MHT CET 2023 12th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

For $$x>1$$, if $$(2 x)^{2 y}=4 \mathrm{e}^{2 x-2 y}$$, then $$\left(1+\log _e 2 x\right)^2 \frac{d y}{d x}$$ is equal to

A
$$\frac{x \log _{\mathrm{e}} 2 x+\log _{\mathrm{e}} 2}{x}$$
B
$$\frac{x \log _e 2 x-\log _e 2}{x}$$
C
$$x \log _{\mathrm{e}} 2 x+\frac{\log _{\mathrm{e}} 2}{x}$$
D
$$x \log _e 2 x-\frac{\log _e 2}{2}$$
2
MHT CET 2023 12th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $$\tan y=\frac{x \sin \alpha}{1-x \cos \alpha}$$ and $$\frac{\mathrm{d} y}{\mathrm{~d} x}=\frac{\mathrm{m}}{x^2+2 \mathrm{n} x+1}$$, then $$\mathrm{m}^2+\mathrm{n}^2$$ is

A
2
B
3
C
1
D
4
3
MHT CET 2023 12th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The approximate value of $$\sin \left(60^{\circ} 0^{\prime} 10^{\prime \prime}\right)$$ is (given that $$\sqrt{3}=1.732,1^{\circ}=0.0175^{\circ}$$ )

A
0.08660243
B
0.0008660243
C
0.8660243
D
0.008660243
4
MHT CET 2023 12th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The derivative of $$\mathrm{f}(\tan x)$$ w.r.t. $$\mathrm{g}(\sec x)$$ at $$x=\frac{\pi}{4}$$ where $$\mathrm{f}^{\prime}(1)=2$$ and $$\mathrm{g}^{\prime}(\sqrt{2})=4$$ is

A
$$\frac{1}{\sqrt{2}}$$
B
$$\sqrt{2}$$
C
1
D
0

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