1
JEE Advanced 2023 Paper 1 Online
Numerical
+4
-0
In a one-litre flask, 6 moles of $A$ undergoes the reaction $A(\mathrm{~g}) \rightleftharpoons P(\mathrm{~g})$. The progress of product formation at two temperatures (in Kelvin), $\mathrm{T}_1$ and $\mathrm{T}_2$, is shown in the figure:

If $\mathrm{T}_1=2 \mathrm{~T}_2$ and $\left(\Delta \mathrm{G}_2^{\Theta}-\Delta \mathrm{G}_1^{\Theta}\right)=\mathrm{RT}_2 \ln \mathrm{x}$, then the value of $\mathrm{x}$ is _______.
$\left[\Delta \mathrm{G}_1^{\Theta}\right.$ and $\Delta \mathrm{G}_2^{\Theta}$ are standard Gibb's free energy change for the reaction at temperatures $\mathrm{T}_1$ and $\mathrm{T}_2$, respectively.]

If $\mathrm{T}_1=2 \mathrm{~T}_2$ and $\left(\Delta \mathrm{G}_2^{\Theta}-\Delta \mathrm{G}_1^{\Theta}\right)=\mathrm{RT}_2 \ln \mathrm{x}$, then the value of $\mathrm{x}$ is _______.
$\left[\Delta \mathrm{G}_1^{\Theta}\right.$ and $\Delta \mathrm{G}_2^{\Theta}$ are standard Gibb's free energy change for the reaction at temperatures $\mathrm{T}_1$ and $\mathrm{T}_2$, respectively.]
Your input ____
2
JEE Advanced 2023 Paper 1 Online
Numerical
+4
-0
The total number of $s p^2$ hybridised carbon atoms in the major product $\mathbf{P}$ (a non-heterocyclic compound) of the following reaction is ______.


Your input ____
3
JEE Advanced 2023 Paper 1 Online
MCQ (Single Correct Answer)
+3
-1
Match the reactions (in the given stoichiometry of the reactants) in List-I with one of their products given in List-II and choose the correct option.
| List - I | List - II |
|---|---|
| (P) $\mathrm{P}_2 \mathrm{O}_3+3 \mathrm{H}_2 \mathrm{O} \rightarrow$ | (1) $\mathrm{P}(\mathrm{O})\left(\mathrm{OCH}_3\right) \mathrm{Cl}_2$ |
| (Q) $\mathrm{P}_4+3 \mathrm{NaOH}+3 \mathrm{H}_2 \mathrm{O} \rightarrow$ | (2) $\mathrm{H}_3 \mathrm{PO}_3$ |
| (R) $\mathrm{PCl}_5+\mathrm{CH}_3 \mathrm{COOH} \rightarrow$ | (3) $\mathrm{PH}_3$ |
| (S) $\mathrm{H}_3 \mathrm{PO}_2+2 \mathrm{H}_2 \mathrm{O}+4 \mathrm{AgNO}_3 \rightarrow$ | (4) $\mathrm{POCl}_3$ |
| (5) $\mathrm{H}_3 \mathrm{PO}_4$ |
4
JEE Advanced 2023 Paper 1 Online
MCQ (Single Correct Answer)
+3
-1
Match the electronic configurations in List-I with appropriate metal complex ions in List-II and choose the correct option.
[Atomic Number: $\mathrm{Fe}=26, \mathrm{Mn}=25, \mathrm{Co}=27$ ]
[Atomic Number: $\mathrm{Fe}=26, \mathrm{Mn}=25, \mathrm{Co}=27$ ]
| List - I | List - II |
|---|---|
| (P) $t_{2 g}^6 e_g^0$ | (1) $\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$ |
| (Q) $t_{2 g}^3 e_g^2$ | (2) $\left[\mathrm{Mn}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$ |
| (R) $\mathrm{e}^2 \mathrm{t}_2^3$ | (3) $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}$ |
| (S) $t_{2 g}^4 e_g^2$ | (4) $\left[\mathrm{FeCl}_4\right]^{-}$ |
| (5) $\left[\mathrm{CoCl}_4\right]^{2-}$ |
Paper Analysis
Total Questions
Chemistry 17
Mathematics 17
Physics 17
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