1
MHT CET 2023 14th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

The diagonal of a square is changing at the rate of $$0.5 \mathrm{~cm} / \mathrm{sec}$$. Then the rate of change of area when the area is $$400 \mathrm{~cm}^2$$ is equal to

A
$$20 \sqrt{2} \mathrm{~cm}^2 / \mathrm{sec}$$
B
$$10 \sqrt{2} \mathrm{~cm}^2 / \mathrm{sec}$$
C
$$\frac{1}{10 \sqrt{2}} \mathrm{~cm}^2 / \mathrm{sec}$$
D
$$\frac{10}{\sqrt{2}} \mathrm{~cm}^2 / \mathrm{sec}$$
2
MHT CET 2023 14th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

Let $$x_0$$ be the point of local minima of $$\mathrm{f}(x)=\overline{\mathrm{a}} \cdot(\overline{\mathrm{b}} \times \overline{\mathrm{c}})$$ where $$\overline{\mathrm{a}}=x \hat{\mathrm{i}}-2 \hat{\mathrm{j}}+3 \hat{\mathrm{k}}, \overline{\mathrm{b}}=-2 \hat{\mathrm{i}}+x \hat{\mathrm{j}}-\hat{\mathrm{k}}, \overline{\mathrm{c}}=7 \hat{\mathrm{i}}-2 \hat{\mathrm{j}}+x \hat{\mathrm{k}}$$, then value of $$\overline{\mathrm{a}} \cdot \overline{\mathrm{b}}$$ at $$x=x_0$$ is

A
15
B
$$-$$15
C
12
D
$$-$$12
3
MHT CET 2023 14th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

Let the curve be represented by $$x=2(\cos t+t \sin t), y=2(\sin t-t \cos t)$$. Then normal at any point '$$t$$' of the curve is at a distance of ______ units from the origin.

A
1
B
0
C
2
D
4
4
MHT CET 2023 14th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

Let $$\mathrm{B} \equiv(0,3)$$ and $$\mathrm{C} \equiv(4,0)$$. The point $$\mathrm{A}$$ is moving on the line $$y=2 x$$ at the rate of 2 units/second. The area of $$\triangle \mathrm{ABC}$$ is increasing at the rate of

A
$$\frac{11}{\sqrt{5}}$$ (units)$$^2$$/ $$\mathrm{sec}$$
B
$$\frac{11}{5}$$ (units)$$^2$$/ $$\mathrm{sec}$$
C
$$\frac{13}{\sqrt{5}}$$ (units)$$^2$$/ $$\mathrm{sec}$$
D
$$\frac{13}{5}$$ (units)$$^2$$/ $$\mathrm{sec}$$
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