1
MHT CET 2026 15th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
If A and B are two events such that $P(A) = \dfrac{2}{3}$, $P(B) = \dfrac{1}{2}$ and $P(A \mid B) = \dfrac{2}{3}$, then $P(A' \cup B) + P(A \cup B') = $
A
$\dfrac{2}{3}$
B
$1$
C
$\dfrac{3}{2}$
D
$\dfrac{5}{6}$
2
MHT CET 2025 5th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

Three numbers are chosen at random from numbers 1 to 20 . The probability that they are consecutive is

A

$\frac{1}{190}$

B

$\frac{1}{120}$

C

$\frac{3}{190}$

D

$\frac{5}{190}$

3
MHT CET 2025 5th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

Two cards are drawn successively with replacement from fair playing 52 cards. let X denote number of kings obtained when two cards are drawn, then $\mathrm{E}\left(\mathrm{X}^2\right)=$

A

$\frac{24}{169}$

B

$\frac{26}{169}$

C

$\frac{27}{169}$

D

$\frac{28}{169}$

4
MHT CET 2025 5th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $\mathrm{X} \sim \mathrm{B}(35, \mathrm{p})$ such that $7 \mathrm{P}(\mathrm{X}=0)=\mathrm{P}(\mathrm{X}=1)$ then the value of $\frac{\mathrm{P}(\mathrm{X}=15)}{\mathrm{P}(\mathrm{X}=20)}$ is equal to

A

$\frac{3125}{7776}$

B

3125

C

7776

D

$\frac{625}{1296}$

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