1
MHT CET 2026 20th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
Four cards are drawn successively with replacement from well shuffled deck of 52 cards, then the probability that only two cards are club cards is ...........
A
$\dfrac{26}{128}$
B
$\dfrac{24}{128}$
C
$\dfrac{27}{128}$
D
$\dfrac{28}{128}$
2
MHT CET 2026 20th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
For the following probability distribution of a random variable $X$, the Expected value and Variance of $X$ are respectively
$X = x$$1$$2$$3$
$P(X = x)$$1/5$$2/5$$2/5$
A
$\dfrac{27}{5}, \dfrac{27}{25}$
B
$\dfrac{11}{5}, \dfrac{14}{25}$
C
$\dfrac{4}{5}, \dfrac{14}{25}$
D
$\dfrac{7}{5}, \dfrac{11}{25}$
3
MHT CET 2026 20th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
A fair die is rolled indefinitely. Player A wins if two consecutive rolls show 3 or 5, and player B wins if two consecutive rolls show 1 or 2 or 4 or 6. The probability that player A wins in the long run is
A
$\dfrac{2}{3}$
B
$\dfrac{5}{21}$
C
$\dfrac{1}{7}$
D
$\dfrac{2}{21}$
4
MHT CET 2026 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
A random variable $X \sim B(n, p)$ follows a binomial distribution with $n = 6$. If $9P(X = 4) = P(X = 2)$, then the probability of success $p$ is..
A
$0.125$
B
$0.75$
C
$0.25$
D
$0.375$

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