MHT CET 2023 10th May Evening Shift | Probability Question 144 | Mathematics

The three ships namely A, B and C sail from India to Africa. If the odds in favour of the ships reaching safely are $$2: 5,3: 7$$ and $$6: 11$$ respectively, then probability of all of them arriving safely is

$$\frac{18}{595}$$

$$\frac{11}{34}$$

$$\frac{196}{217}$$

$$\frac{1}{595}$$

MHT CET 2023 10th May Evening Shift

MCQ (Single Correct Answer)

-0

If the sum of mean and variance of a Binomial Distribution is $$\frac{15}{2}$$ for 10 trials, then the variance is

1.5

2.5

4.5

3.5

MHT CET 2023 10th May Evening Shift

MCQ (Single Correct Answer)

-0

In a game, 3 coins are tossed. A person is paid ₹ 7 /-, if he gets all heads or all tails; and he is supposed to pay ₹ 3 /-, if he gets one head or two heads. The amount he can expect to win on an average per game is ₹

$$-$$0.5

0.5

$$-$$1

MHT CET 2023 10th May Evening Shift

MCQ (Single Correct Answer)

-0

A fair die is tossed twice in succession. If $$\mathrm{X}$$ denotes the number of sixes in two tosses, then the probability distribution of $$\mathrm{X}$$ is given by

$$\mathrm{X=}x$$	0	1	2
$$\mathrm{P(X=}x)$$	$$\frac{25}{36}$$	$$\frac{1}{36}$$	$$\frac{5}{18}$$

$$\mathrm{X=}x$$	0	1	2
$$\mathrm{P(X=}x)$$	$$\frac{5}{18}$$	$$\frac{1}{36}$$	$$\frac{25}{36}$$

$$\mathrm{X=}x$$	0	1	2
$$\mathrm{P(X=}x)$$	$$\frac{25}{36}$$	$$\frac{5}{18}$$	$$\frac{1}{36}$$

$$\mathrm{X=}x$$	0	1	2
$$\mathrm{P(X=}x)$$	$$\frac{5}{18}$$	$$\frac{25}{36}$$	$$\frac{1}{36}$$

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