MHT CET 2024 2nd May Morning Shift | Probability Question 56 | Mathematics

A bag contains 4 Red and 6 Black balls. A ball is drawn at random from the bag, its colour is observed and this ball along with 3 additional balls of the same colour are returned to the bag. If now a ball is drawn at random from the bag, then the probability that this drawn ball is red is

$\frac{41}{65}$

$\frac{24}{65}$

$\frac{26}{65}$

$\frac{28}{65}$

MHT CET 2024 2nd May Morning Shift

MCQ (Single Correct Answer)

-0

If a discrete random variable X takes values $0,1,2,3, \ldots \ldots$. with probability $\mathrm{P}(\mathrm{X}=x)=\mathrm{k}(x+1) 5^{-x}$, where k is a constant, then $\mathrm{P}(\mathrm{X}=0)$ is

$\frac{7}{25}$

$\frac{16}{25}$

$\frac{18}{25}$

$\frac{19}{25}$

MHT CET 2024 2nd May Morning Shift

MCQ (Single Correct Answer)

-0

Ten bulbs are drawn successively, with replacement, from a lot containing $10 \%$ defective bulbs, then the probability that there is at least one defective bulb, is

$1-\left(\frac{1}{10}\right)^{10}$

$1-\left(\frac{3}{10}\right)^{10}$

$1-\left(\frac{9}{10}\right)^{10}$

$1-\left(\frac{7}{10}\right)^{10}$

MHT CET 2023 14th May Evening Shift

MCQ (Single Correct Answer)

-0

A fair die with numbers 1 to 6 on their faces is thrown. Let $$\mathrm{X}$$ denote the number of factors of the number, on the uppermost face, then the probability distribution of $$\mathrm{X}$$ is

$$\mathrm{X=}x$$	1	2	3	4
$$\mathrm{P(x=}x)$$	$$\frac{1}{6}$$	$$\frac{1}{2}$$	$$\frac{1}{6}$$	$$\frac{1}{6}$$

$$\mathrm{X=}x$$	1	2	3	4
$$\mathrm{P(x=}x)$$	$$\frac{1}{6}$$	$$\frac{1}{6}$$	$$\frac{1}{6}$$	$$\frac{1}{2}$$

$$\mathrm{X=}x$$	1	2	3	4
$$\mathrm{P(x=}x)$$	$$\frac{1}{6}$$	$$\frac{1}{6}$$	$$\frac{1}{6}$$	$$\frac{1}{6}$$

$$\mathrm{X=}x$$	1	2	3	4
$$\mathrm{P(x=}x)$$	$$\frac{1}{6}$$	$$\frac{1}{6}$$	$$\frac{1}{2}$$	$$\frac{1}{6}$$

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