MHT CET 2024 2nd May Evening Shift | Probability Question 53 | Mathematics

Let in a Binomial distribution, consisting of 5 independent trials, probabilities of exactly 1 and 2 successes be 0.4096 and 0.2048 respectively. Then the probability of getting exactly 3 successes is equal to

$\frac{80}{243}$

$\frac{40}{7243}$

$\frac{32}{625}$

$\frac{128}{625}$

MHT CET 2024 2nd May Evening Shift

MCQ (Single Correct Answer)

-0

The probability distribution of a random variable X is given by

$\mathrm{X=}x_i$:	0	1	2	3	4
$\mathrm{P(X=}x_i)$ :	0.4	0.3	0.1	0.1	0.1

Then the variance of X is

1.76

2.45

3.2

4.8

MHT CET 2024 2nd May Evening Shift

MCQ (Single Correct Answer)

-0

Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three persons apply for the same house is

$\frac{1}{9}$

$\frac{2}{9}$

$\frac{7}{9}$

$\frac{8}{9}$

MHT CET 2024 2nd May Morning Shift

MCQ (Single Correct Answer)

-0

A bag contains 4 Red and 6 Black balls. A ball is drawn at random from the bag, its colour is observed and this ball along with 3 additional balls of the same colour are returned to the bag. If now a ball is drawn at random from the bag, then the probability that this drawn ball is red is

$\frac{41}{65}$

$\frac{24}{65}$

$\frac{26}{65}$

$\frac{28}{65}$

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