1
MHT CET 2025 5th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

Three numbers are chosen at random from numbers 1 to 20 . The probability that they are consecutive is

A

$\frac{1}{190}$

B

$\frac{1}{120}$

C

$\frac{3}{190}$

D

$\frac{5}{190}$

2
MHT CET 2025 5th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

Two cards are drawn successively with replacement from fair playing 52 cards. let X denote number of kings obtained when two cards are drawn, then $\mathrm{E}\left(\mathrm{X}^2\right)=$

A

$\frac{24}{169}$

B

$\frac{26}{169}$

C

$\frac{27}{169}$

D

$\frac{28}{169}$

3
MHT CET 2025 5th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $\mathrm{X} \sim \mathrm{B}(35, \mathrm{p})$ such that $7 \mathrm{P}(\mathrm{X}=0)=\mathrm{P}(\mathrm{X}=1)$ then the value of $\frac{\mathrm{P}(\mathrm{X}=15)}{\mathrm{P}(\mathrm{X}=20)}$ is equal to

A

$\frac{3125}{7776}$

B

3125

C

7776

D

$\frac{625}{1296}$

4
MHT CET 2025 5th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

A student studies for X number of hours during a randomly selected school day. The probability that X can take the values, has the following form, where k is some constant.

$$ \mathrm{P}(\mathrm{X}=x)= \begin{cases}0.2, & \text { if } x=0 \\ \mathrm{k} x, & \text { if } x=1 \text { or } 2 \\ \mathrm{k}(6-x), & \text { if } x=3 \text { or } 4 \\ 0, & \text { otherwise }\end{cases} $$

The probability that the student studies for at most two hours is

A

0.1

B

0.5

C

0.3

D

0.7

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